Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
20 days
22 1 days
2
25 days
30 days
Answer: Option
Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30

B's 1 day's work = 1
90

(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45

A and B together can do the work in 45 = 22 1 days.
2 2

Discussion:
284 comments Page 14 of 29.

Nagarjun said:   2 decades ago
@Vikas

Its just cross multiplication.
If the difference is 2 days then b takes 3 days
If the difference is 60 days then b takes x days

Hence, x= (60*3)/2.

I think you got it now.

Pramod nepal said:   8 years ago
Let see @Shaman.

A finish work in x day and B can 5x day. Then we can do A+B= 1/x +1/5x.

We have A+B = 50,

50 = 5x/6 after sol x= 60 it means A can do in 60 min and B 300 min.

Suresh said:   9 years ago
A is 3 times more efficient than B,
A=3B
A do the work less than 60 days compared to B,
A-60=B.

So, we can write it as,
A = 3(A+60)
A = 3A+180
2A = 180
A = 90
90-60 = B
B = 30.

Taukir said:   1 year ago
A takes time = x days.
So, B takes time = 3x days
Now, 3x - x = 60 days
X = 30
3x = 90
1/30 + 1/90 = 1/20 (working together in 1 day).
So, They can do the whole work in 20 days.
(87)

Harsha said:   2 years ago
A takes x-60 days.
B takes x days.
If A does work in 1 day then B takes 3 days.
So,
1/(x-60) = 1/x
Solving this we get x = 90
Now, A+B can do work in 1/90 + 3/90.
We get 45/2.
(49)

M ahmad said:   1 decade ago
A can do the job in x days.
B can same job in 3x days.

3x=x+60 by B.
x=30.

One day work by A and B = 1/30+1/90 = 4/90 = 2/45.

Whole job done by A and B = 45/2 = 22.5 days.

Sahil Husain said:   9 years ago
A=3B ----------(1)
A-60=B----------(2) from equation 1 & 2

3B-60 = B
B=30 and A = 90
(A+B)'S 1 day work =1\90+1\30 = 2\45,
So (A+B)'s work = 45\2 = 22 1\2.

Aya adel said:   2 years ago
a : b
1 : 3.

And x-60:x

Then 3(x - 60) = x.
3x-180 = x,
2x = 180,
x = 90.

a = 90 - 60 = 30
b = 90
1\a + 1\b = 1\30 + 1\90 = 2\45.
a + b = 45\2.
So, the answer is 22 1\2.
(57)

HARINI said:   4 years ago
Given;

A = 3B;
A = B - 60.

Substitute A = 3B in 2nd equation(a=b-60).
3B = B-60
B = 30.

Therefore; A = 3B = 90.

A+B = (1/30 + 1/90) = 2/45.
So, the answer is 22(1/2).
(24)

Tiya said:   8 years ago
Please solve this question.

If the ratio of work efficiency of A and B is 3:2. If A and B together finish a work in 5 days in how much days B alone complete the work?


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