Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
2 |
So, A takes 30 days to do the work.
A's 1 day's work = | 1 |
30 |
B's 1 day's work = | 1 |
90 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
30 | 90 | 90 | 45 |
![]() |
45 | = 22 | 1 | days. |
2 | 2 |
Discussion:
281 comments Page 13 of 29.
Kavya said:
1 decade ago
A is twice as good a workmen as B and together they can finish a piece of work in 18days. In how many days will A alone finish the work?
Can we solve the above problem using the formula k*x/k^2-1.
Can we solve the above problem using the formula k*x/k^2-1.
Rajeesh kumar said:
5 years ago
@All.
We can easily convert it to a linear equation.
Let B requires x days and forA it is y
it is given,x = 3y.
In the same way;
X-60=Y
By solving we have 2x- 180=0 :.x=90.
and y=90 - 60 = 30.
We can easily convert it to a linear equation.
Let B requires x days and forA it is y
it is given,x = 3y.
In the same way;
X-60=Y
By solving we have 2x- 180=0 :.x=90.
and y=90 - 60 = 30.
Ameer said:
6 years ago
Thank you, excellent explanation.
a = 3b --> (1).
a-b = 60.
3b-b = 60.
2b = 60.
b = 30.
If b = 30 then from 1a = 3 x 30 = 90.
Now,
= 1/30+1/90.
= 3+1/90.
= 4/90 = 2/45.
= 45/2 = 22.5 days.
a = 3b --> (1).
a-b = 60.
3b-b = 60.
2b = 60.
b = 30.
If b = 30 then from 1a = 3 x 30 = 90.
Now,
= 1/30+1/90.
= 3+1/90.
= 4/90 = 2/45.
= 45/2 = 22.5 days.
Jeev said:
6 years ago
3A = B.
If 60 is less than b(then 60 is two times of a)
then A=30,
b = 3 * 30 = 90,
a+b=1/30+1/90,
3*1/90+1/90,
(3+1)/90.
Where 4/90(to get days upside down).
90/4 = 22(1/2) days.
If 60 is less than b(then 60 is two times of a)
then A=30,
b = 3 * 30 = 90,
a+b=1/30+1/90,
3*1/90+1/90,
(3+1)/90.
Where 4/90(to get days upside down).
90/4 = 22(1/2) days.
MOSA said:
6 years ago
Let a did this work in X days.
B can do it in 3x days.
X+60=3x.
X=30.
It means A can complete this work in 30 days and B in 90 days;
Capacity of;
A is 3.
B is 4.
A+B= 4.
TIME =90/4.
B can do it in 3x days.
X+60=3x.
X=30.
It means A can complete this work in 30 days and B in 90 days;
Capacity of;
A is 3.
B is 4.
A+B= 4.
TIME =90/4.
Pratyush said:
1 decade ago
Can we do it like this:
a = 3b....(1).
a-b = 60.
3b-b = 60.
2b = 60.
b = 30.
If b = 30 then from 1a = 3x30 = 90.
Now,
= 1/30+1/90.
= 3+1/90.
= 4/90 = 2/45.
= 45/2 = 22.5 days.
a = 3b....(1).
a-b = 60.
3b-b = 60.
2b = 60.
b = 30.
If b = 30 then from 1a = 3x30 = 90.
Now,
= 1/30+1/90.
= 3+1/90.
= 4/90 = 2/45.
= 45/2 = 22.5 days.
Jezan said:
1 decade ago
According to this question if A is x, B will be x+60
1/3=x/x+60
3x=x+60
2x=6
x=30
A+B'S ONE DAY WORK=1/30+1/90=2/45
SO WHOLE WORK S= 45/2( UPSIDE DOWN)
22.5 DAYS.
HOPE ALL LL GET DIS
1/3=x/x+60
3x=x+60
2x=6
x=30
A+B'S ONE DAY WORK=1/30+1/90=2/45
SO WHOLE WORK S= 45/2( UPSIDE DOWN)
22.5 DAYS.
HOPE ALL LL GET DIS
Nagarjun said:
1 decade ago
@Vikas
Its just cross multiplication.
If the difference is 2 days then b takes 3 days
If the difference is 60 days then b takes x days
Hence, x= (60*3)/2.
I think you got it now.
Its just cross multiplication.
If the difference is 2 days then b takes 3 days
If the difference is 60 days then b takes x days
Hence, x= (60*3)/2.
I think you got it now.
Pramod nepal said:
8 years ago
Let see @Shaman.
A finish work in x day and B can 5x day. Then we can do A+B= 1/x +1/5x.
We have A+B = 50,
50 = 5x/6 after sol x= 60 it means A can do in 60 min and B 300 min.
A finish work in x day and B can 5x day. Then we can do A+B= 1/x +1/5x.
We have A+B = 50,
50 = 5x/6 after sol x= 60 it means A can do in 60 min and B 300 min.
Suresh said:
8 years ago
A is 3 times more efficient than B,
A=3B
A do the work less than 60 days compared to B,
A-60=B.
So, we can write it as,
A = 3(A+60)
A = 3A+180
2A = 180
A = 90
90-60 = B
B = 30.
A=3B
A do the work less than 60 days compared to B,
A-60=B.
So, we can write it as,
A = 3(A+60)
A = 3A+180
2A = 180
A = 90
90-60 = B
B = 30.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers