Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
284 comments Page 12 of 29.
Logesh said:
1 year ago
Finding the days for B and A:
The ratio difference is 2 and the day difference is 60.
So, for every single inc in ratio, it will increase by 30 days.
From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).
The ratio difference is 2 and the day difference is 60.
So, for every single inc in ratio, it will increase by 30 days.
From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).
(10)
Monika said:
1 decade ago
We have a direct formula for these kind of questions .. i.e.,
Work done together is given by = (m*d)/(m^2 - 1),
Where d is no of days taken by B and m is no of time A is faster than B,
Therefore = (3*60)/(3^2-1) = 22.5.
Work done together is given by = (m*d)/(m^2 - 1),
Where d is no of days taken by B and m is no of time A is faster than B,
Therefore = (3*60)/(3^2-1) = 22.5.
Subhendu said:
6 years ago
(3-1)=2------>60
1------>30
3------->90.
1's day work for A= 1/30
1's day work for b=1/90
Both 1's day work=(1/30+1/90)
= 4/90.
Total day = 90/4.
= 22(1/2).
The answer is B.
1------>30
3------->90.
1's day work for A= 1/30
1's day work for b=1/90
Both 1's day work=(1/30+1/90)
= 4/90.
Total day = 90/4.
= 22(1/2).
The answer is B.
Dnyaneshwar said:
5 years ago
A = 3B
Suppose workdone in 1 day by 'B'= 1/n.
Suppose workdone in 1 day by 'A'= 1/(n-60).
We get eqn;
1/(n-60) = 3(1/n).
So, n =90 days (Time taken by B to complete the work).
A= 30 days.
A+B = (1/30)+(1/90) = 22.5.
Suppose workdone in 1 day by 'B'= 1/n.
Suppose workdone in 1 day by 'A'= 1/(n-60).
We get eqn;
1/(n-60) = 3(1/n).
So, n =90 days (Time taken by B to complete the work).
A= 30 days.
A+B = (1/30)+(1/90) = 22.5.
Manju gouda said:
1 decade ago
Let us take B's work days be 'x'.
Then A's will be x/3.
Given difference is 60.
Therefore x-x/3 = 60 on solving x = 90.
Therefore B days = 90 & A = 30.
A&B together will be (90*30)/(90+30) = 22.5 days.
Then A's will be x/3.
Given difference is 60.
Therefore x-x/3 = 60 on solving x = 90.
Therefore B days = 90 & A = 30.
A&B together will be (90*30)/(90+30) = 22.5 days.
Padma said:
4 years ago
Here a simple calculation is;
A takes 1 part and B takes 3 parts.
\
So A:B ratio is 1:3.
total 4p.and the difference is 2,they did work in 60 days so 60p.
4p=60.
p=15/1.
B total working days 15*3=45.
W/t is 45/2.
A takes 1 part and B takes 3 parts.
\
So A:B ratio is 1:3.
total 4p.and the difference is 2,they did work in 60 days so 60p.
4p=60.
p=15/1.
B total working days 15*3=45.
W/t is 45/2.
(4)
Vpk said:
2 years ago
A B
(x-60) x
B=3A;
x = 3(x-60);
x = 3x - 180;
2x = 180;
x = 90;
B = 90 days
A = 30 days.
Work done in 1 day A and B together => 1/30 + 1/90=2/45;
Whole work is will be done 45/2=>22 1/2;
(x-60) x
B=3A;
x = 3(x-60);
x = 3x - 180;
2x = 180;
x = 90;
B = 90 days
A = 30 days.
Work done in 1 day A and B together => 1/30 + 1/90=2/45;
Whole work is will be done 45/2=>22 1/2;
(104)
PARASHAR said:
1 decade ago
Simple yaar.
>A is thrice as good as workman as B and therefore is able to finish a job in 60 days=IF B TAKE 90 DAYS THEN A WILL TAKE 30 (60 DAYS LESS).
>1/30 (PLUS) 1/60=4/90==>90/4==>22. 5 SIMPLE.
>A is thrice as good as workman as B and therefore is able to finish a job in 60 days=IF B TAKE 90 DAYS THEN A WILL TAKE 30 (60 DAYS LESS).
>1/30 (PLUS) 1/60=4/90==>90/4==>22. 5 SIMPLE.
Rohi said:
8 years ago
Ratio of times taken by A and B = 1:3.
Means B will take 3 times which A will do in 1 time.
If difference of time is 2 days, B takes 3 days,
If the difference of time is 10 days, B takes (3/2) * 10 =15 days.
Means B will take 3 times which A will do in 1 time.
If difference of time is 2 days, B takes 3 days,
If the difference of time is 10 days, B takes (3/2) * 10 =15 days.
Anshul said:
1 decade ago
We can solve this question easily.
A:B = 1:3.
Difference is 60.
Hence ratio becomes:
A:B = 30:90 = 1:3.
Here we can see diff is 60.
So our answer will be 90*30/90+30 = 270/12.
= 90/4 = 45/2 = 22+1/2.
A:B = 1:3.
Difference is 60.
Hence ratio becomes:
A:B = 30:90 = 1:3.
Here we can see diff is 60.
So our answer will be 90*30/90+30 = 270/12.
= 90/4 = 45/2 = 22+1/2.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers