Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
20 days
22 1 days
2
25 days
30 days
Answer: Option
Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30

B's 1 day's work = 1
90

(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45

A and B together can do the work in 45 = 22 1 days.
2 2

Discussion:
281 comments Page 11 of 29.

Jagadish Behera said:   3 years ago
"A" is 3 times more than" B" (efficiency)

Difference = 60 days

3x-x = 60

X = 30days This is" B"

A=3 * 30 = 90 days.

So Total work =180

A=2 WORK
B=6 WORK

A+B TOGETHER CAN DO IN 180/8 = 22.5 DAYS.
(14)

Malay kanti Bhunia said:   1 decade ago
X - 3X = 60.

X = 30.

A done works 30 days and B done the work 90 days.

A work done in 1 day 1/30 part.

B work done in 1 day 1/90 part.

A and B work together in 1 day (1/30+1/90) = 2/45 part.

Time taken in this work 22.5 days.

Venkatesh said:   1 decade ago
Hi friends just read, A's works 3 times than B so work ration 3:1 and time ratio will be 1:3 in the question they ask for time so 3/(3-1)*60=90.

A 3 times better 3/90=1/30(1 days work) B 1/90 1days work together 1/90+1/30=answer.

Farheen Pathan said:   2 years ago
As A is thrice good than B then the Ratio of work done together is:

A : B
3 : 1

As A do work 60 days less than B , Suppose;
A : B
30 : 90---->LCM = 90,
(30×3)----->3u of A+1u of B =4u,
I.e 90/4 = 45/2 = 22(1/2).
(35)

Nitin singh parihar said:   1 decade ago
Let B do the work in 'x' days.

So, A will take (x-60) days.

Now, ratio of A:B=1:3 (given in ques).

So, 1/3=x-60/x.

=> x=90 (B's 1 day work).

So, A's work=30 days.

Working together=1/30+1/90.

=45/2 days.

Easy and simple.

Ankita said:   1 decade ago
Suppose A takes x days.

Then, B will take 3x days.

From question, 3x-x = 60.

=> x = 30.

=> A takes 30 days and B takes 90 days.

Together they will take = 30*90/30+90.

= 30*90/120.

= 90/4.

= 22.5 or 22 1/2 days (ans).

Shreya said:   7 years ago
@All.

This is the easiest & shortest!.

Let a be x whereas b = 3x.
So, 3x " x = 60. x = 30.
therefore a = 30, b = 90.
so when they work together-> 1/30+1/60 = 4/90 = 2/45.

Together they can do the work in 22 (1/2) days.

Apsar Khan said:   4 years ago
If A completes the work in x days, B will do the same in 3x days.

3x - x = 60.
2x = 60.
Then x = 30 and 3x = 90.
(A + B) 's 1 day's work.
=1/30 + 1/90.
= 4/90.

So, A and B together will do the work in;

= 90/4.
=>22 and 1/2.
(1)

Logesh said:   1 year ago
Finding the days for B and A:

The ratio difference is 2 and the day difference is 60.

So, for every single inc in ratio, it will increase by 30 days.

From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).
(10)

Monika said:   1 decade ago
We have a direct formula for these kind of questions .. i.e.,

Work done together is given by = (m*d)/(m^2 - 1),

Where d is no of days taken by B and m is no of time A is faster than B,
Therefore = (3*60)/(3^2-1) = 22.5.


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