Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
176 comments Page 7 of 18.
Sriram.g said:
7 years ago
Both are travelling at different speed but in the same amount of time.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
Ameer said:
7 years ago
@All.
According to me;
1st hour 10 = 14,
2nd hour 20 = 28,
3rd hour 30 = 42,
4th hour 40 = 56,
5th hour 50 = 70,
IF IN ONE HOUR HE IS DOING 14, THEN IN THE FIFTH HOUR (14*5=60) TIMES UP.
At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km.
So, 70 - 50 = 20. I think u got it.
OR
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
According to me;
1st hour 10 = 14,
2nd hour 20 = 28,
3rd hour 30 = 42,
4th hour 40 = 56,
5th hour 50 = 70,
IF IN ONE HOUR HE IS DOING 14, THEN IN THE FIFTH HOUR (14*5=60) TIMES UP.
At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km.
So, 70 - 50 = 20. I think u got it.
OR
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
Ameer said:
8 years ago
@Jayesh.
You make it very easy to understand. Thanks.
You make it very easy to understand. Thanks.
Dadi Ganesh said:
8 years ago
Well said, Good explanation. Thanks @Jayesh.
Jayesh said:
8 years ago
@All.
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
Pradyumnan said:
8 years ago
I am understanding now. Thanks All.
Ramu Dhakal said:
8 years ago
Time = Distance/Speed.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
Palani said:
8 years ago
Friends, we should first understand the concept.
The man walks at 10kmph covered certain distance X. Then man instead of walks at 14kmph covered certain distance X. So both are covering the distance x first. Then he will take an extra time to cover 20km.
The Time difference
D is=20km.
Formula=D = D[a/a-b].
=20(10/4)=50km.
The man walks at 10kmph covered certain distance X. Then man instead of walks at 14kmph covered certain distance X. So both are covering the distance x first. Then he will take an extra time to cover 20km.
The Time difference
D is=20km.
Formula=D = D[a/a-b].
=20(10/4)=50km.
Shivani k said:
8 years ago
The question says that if he travelled 14km/hr instead of 10km/hr he would cover 20km more so
(14 -10)= 4 km/hr.
Distance covered with speed of 4km/hr=20km.
1km/hr= 20/4,
= 5km.
Actual distance covered with 10km/hr.
10 * 5 =50 km.
(14 -10)= 4 km/hr.
Distance covered with speed of 4km/hr=20km.
1km/hr= 20/4,
= 5km.
Actual distance covered with 10km/hr.
10 * 5 =50 km.
Ani said:
8 years ago
Why not X/14= (x+20) /10?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers