Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
176 comments Page 16 of 18.
Palani said:
8 years ago
Friends, we should first understand the concept.
The man walks at 10kmph covered certain distance X. Then man instead of walks at 14kmph covered certain distance X. So both are covering the distance x first. Then he will take an extra time to cover 20km.
The Time difference
D is=20km.
Formula=D = D[a/a-b].
=20(10/4)=50km.
The man walks at 10kmph covered certain distance X. Then man instead of walks at 14kmph covered certain distance X. So both are covering the distance x first. Then he will take an extra time to cover 20km.
The Time difference
D is=20km.
Formula=D = D[a/a-b].
=20(10/4)=50km.
Ramu Dhakal said:
8 years ago
Time = Distance/Speed.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
Pradyumnan said:
8 years ago
I am understanding now. Thanks All.
Jayesh said:
8 years ago
@All.
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
Dadi Ganesh said:
8 years ago
Well said, Good explanation. Thanks @Jayesh.
Ameer said:
8 years ago
@Jayesh.
You make it very easy to understand. Thanks.
You make it very easy to understand. Thanks.
Ameer said:
7 years ago
@All.
According to me;
1st hour 10 = 14,
2nd hour 20 = 28,
3rd hour 30 = 42,
4th hour 40 = 56,
5th hour 50 = 70,
IF IN ONE HOUR HE IS DOING 14, THEN IN THE FIFTH HOUR (14*5=60) TIMES UP.
At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km.
So, 70 - 50 = 20. I think u got it.
OR
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
According to me;
1st hour 10 = 14,
2nd hour 20 = 28,
3rd hour 30 = 42,
4th hour 40 = 56,
5th hour 50 = 70,
IF IN ONE HOUR HE IS DOING 14, THEN IN THE FIFTH HOUR (14*5=60) TIMES UP.
At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km.
So, 70 - 50 = 20. I think u got it.
OR
14-10 = 4km/hr.
4km/hr = 20km travelled.
so 1hr = 5km,
then 10km/hr = 10 * 5 = 50.
Sriram.g said:
7 years ago
Both are travelling at different speed but in the same amount of time.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
Zayan said:
7 years ago
Why is there x/10?
Rayan said:
7 years ago
The another method.
Let's, time will be t.
so, 14t-10t=20,
or. 4t=20,
or, t=5.
so, the total distance is 5*0 = 50.
Let's, time will be t.
so, 14t-10t=20,
or. 4t=20,
or, t=5.
so, the total distance is 5*0 = 50.
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