Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
173 comments Page 16 of 18.
Sriram.g said:
6 years ago
Both are travelling at different speed but in the same amount of time.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
Zayan said:
6 years ago
Why is there x/10?
Rayan said:
6 years ago
The another method.
Let's, time will be t.
so, 14t-10t=20,
or. 4t=20,
or, t=5.
so, the total distance is 5*0 = 50.
Let's, time will be t.
so, 14t-10t=20,
or. 4t=20,
or, t=5.
so, the total distance is 5*0 = 50.
Arun said:
6 years ago
It's based on per hour that means time is constant. And when time is constant distance and speed will be directly proportional.
Speed : 14 : 10
=> 7:5.
Since distance is directly proportional.
Its ratio also will be 7:5
20 more means the difference of 7-5.
Speed : 14 : 10
=> 7:5.
Since distance is directly proportional.
Its ratio also will be 7:5
20 more means the difference of 7-5.
Sandeep jayker said:
6 years ago
Distance= (a/x-y) * y.
a=20km
X=14 KMPH.
Y=10 KMPH.
(20KM/14KMPH-10KMPH) * 10KMPH.
(20KM/4KMPH) * 10KMPH.
So, the answer is 50KM.
a=20km
X=14 KMPH.
Y=10 KMPH.
(20KM/14KMPH-10KMPH) * 10KMPH.
(20KM/4KMPH) * 10KMPH.
So, the answer is 50KM.
Bimal limbu said:
6 years ago
70 is the answer.
Jinia siga said:
6 years ago
I do not understand why x+20 has taken in solution?
Amit said:
5 years ago
The correct answer should be 70 as the value of x is 50 at the speed of 10 km/hr but at the speed of 14 km hr is 20 more.
Kamal said:
5 years ago
Present speed = 14 km/h & Regular speed =10 km/h.
Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
VishnuGpd said:
5 years ago
A:B
14:10
7:5.
Difference is 2parts.
2part=20km{actual difference).
1part=10km.
Multiply B part that is 5*10=50.
14:10
7:5.
Difference is 2parts.
2part=20km{actual difference).
1part=10km.
Multiply B part that is 5*10=50.
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