Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
176 comments Page 15 of 18.
Bhat said:
1 decade ago
Difference between distance i.e. 14-10 = 4.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Gaurav Ralhan said:
1 decade ago
But it is not written that time instance is same.
Sohail said:
1 decade ago
We can do this in simple unitary method; like,
If the man travels at the speed of 14 km/hr he covers 20 extra km than if he travels at 10 km/hr.
Therefore we can see this extra 4 km/hr speed helps him to cover 20 km.
Now we can write in:
4 km/hr speed he covers 20 km;
1 km/hr speed he cover 20/4 km;
Now in (original speed) 10 km/hr speed he covers 20/4 x 10 = 50 km.
If the man travels at the speed of 14 km/hr he covers 20 extra km than if he travels at 10 km/hr.
Therefore we can see this extra 4 km/hr speed helps him to cover 20 km.
Now we can write in:
4 km/hr speed he covers 20 km;
1 km/hr speed he cover 20/4 km;
Now in (original speed) 10 km/hr speed he covers 20/4 x 10 = 50 km.
Anjith said:
1 decade ago
Hi,
The man travels at a speed of 14, but he assumed to travel at a speed of 10 kmph.
Means the man covered 70km, but he assumed to cover is 50 km.
Hence the actual distance covered by the man is 70 kms, and it is the answer.
Please let me know if I am wrong.
The man travels at a speed of 14, but he assumed to travel at a speed of 10 kmph.
Means the man covered 70km, but he assumed to cover is 50 km.
Hence the actual distance covered by the man is 70 kms, and it is the answer.
Please let me know if I am wrong.
Laxman said:
1 decade ago
The actual distance should be the 10hr/km i.e. (50km ) + extra 20KM = 70 km?
Tanay said:
1 decade ago
In 4 kmph he walk more 20 km.
So in 1 kmph he walks (20/4) =5 km.
Thus in 10 kmph he walks (5*10) =50 km (actual distance).
So in 1 kmph he walks (20/4) =5 km.
Thus in 10 kmph he walks (5*10) =50 km (actual distance).
Anand said:
1 decade ago
Ilesh logical thinking sweet and simlpe...
Raji said:
1 decade ago
Ilesh method is good procedure than others because in question there is no clarity that the time is same.
Nandhu said:
1 decade ago
How you getting this (x+20) /14.
Mmk91 said:
1 decade ago
still confusion guys
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