Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 11 of 18.
Bishal gupta said:
10 years ago
Easy way:
Actually travelled 10 kmph.
If travelled 14 kmph then he would have travelled 20 kmph more.
14-10 = 4.
Means 20/4 = 5.
Then actually he travelled 10 kmph.
So, 10*5 = 50 answer.
Actually travelled 10 kmph.
If travelled 14 kmph then he would have travelled 20 kmph more.
14-10 = 4.
Means 20/4 = 5.
Then actually he travelled 10 kmph.
So, 10*5 = 50 answer.
Hemanth said:
10 years ago
Here in this question both the times are equal. So we use s1/d1 = s2/d2.
Therefore: 10/x = 14/x+20.
10x+200 = 14x.
4x = 200.
x = 50.
Therefore: 10/x = 14/x+20.
10x+200 = 14x.
4x = 200.
x = 50.
Sonia said:
10 years ago
Time is considered as equal in both cases because of its average speed. Look over the question again. Speed is 14kmph & 10 kmph. It means 14 km travelled in one hour and 10 km travelled in one hour. So the time in both cases is the same.
Bdboy Hasan said:
10 years ago
Speed increase 14 - 10 = 4 kmph and so that distance increase 20 km.
When distance increases 4 km then time is 1 hour.
When distance increases 1 km then time is 1/4 hour.
When distance increases 20 km then time is 20/4 hour or 5 hours.
So, he journeyed 5 hours in 10 kmph.
So, distance is 5 * 10 = 50 hour.
Note : This technique is more useful for quick calculation.
When distance increases 4 km then time is 1 hour.
When distance increases 1 km then time is 1/4 hour.
When distance increases 20 km then time is 20/4 hour or 5 hours.
So, he journeyed 5 hours in 10 kmph.
So, distance is 5 * 10 = 50 hour.
Note : This technique is more useful for quick calculation.
Kalinga kumar said:
9 years ago
We know,
Time = Distance/Speed.
Let's take original distance is X.
Given,
Speed is 10km/1hr and 14km/1hr.
Now we can write,
1hr = X distance/10 speed --> (1).
Similarly,
1hr = (X + 20) distance/14 speed --> (2).
Now, put the value of (1) in (2).
We will get,
X/10 = (X + 20)/14.
14X = 10X + 200.
4X = 200.
X = 50.
Time = Distance/Speed.
Let's take original distance is X.
Given,
Speed is 10km/1hr and 14km/1hr.
Now we can write,
1hr = X distance/10 speed --> (1).
Similarly,
1hr = (X + 20) distance/14 speed --> (2).
Now, put the value of (1) in (2).
We will get,
X/10 = (X + 20)/14.
14X = 10X + 200.
4X = 200.
X = 50.
Kavitha said:
9 years ago
@Manish Nair.
Thanks for your solution.
Thanks for your solution.
Gtg said:
9 years ago
I did not understand the concept.
Atiya said:
9 years ago
Thanks for all your hard work and solution.
Ziyauddin said:
9 years ago
@Gowtham.
Thanks, you expressed clearly.
Thanks, you expressed clearly.
Sidzwozz said:
9 years ago
@Ilesh.
Explained very well.
Explained very well.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers