Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 3)
3.
The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
Answer: Option
Explanation:
Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
| Then, 10x = 4y or y = | 5 | x. |
| 2 |
15x + 2y = 4000
 15x + 2 x |
5 | x = 4000 |
| 2 |
20x = 4000
x = 200.
| So, y = |  |
5 | x 200 |  |
= 500. |
| 2 |
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
Discussion:
32 comments Page 1 of 4.
Rashmi said:
1 decade ago
10 chairs = 4 tables => 5 chairs = 2 tables....(i)
15 chairs + 2 tables = 4000 (given)
=> 15 chairs + 5 chairs = 4000 from (i)
=> 20 chairs = rs4000
=> 10 chairs = 2000 = 4 tables....(ii)
=> 1 chair = 2000/10=200
=> 12 chairs= 200*12= 2400 and 1 table = 2000/4 from (ii)
=>3 tables=500*3=1500
.
. . 12c+3t = 2400+1500= 3900 (ans).
15 chairs + 2 tables = 4000 (given)
=> 15 chairs + 5 chairs = 4000 from (i)
=> 20 chairs = rs4000
=> 10 chairs = 2000 = 4 tables....(ii)
=> 1 chair = 2000/10=200
=> 12 chairs= 200*12= 2400 and 1 table = 2000/4 from (ii)
=>3 tables=500*3=1500
.
. . 12c+3t = 2400+1500= 3900 (ans).
Bibarsha said:
9 years ago
=> 10 chair = 4 tables.
Then, 5 chair= 2 tables.
So, 15 chair + 2 table= 4000/- (given).
Means;
5c = 1000/-.
5c = 1000/-.
5c = 1000/-.
2t = 1000 (since 5c=2tables).
Then, 1 table = 1000/2.
=500/-.
1 chair = 1000/5.
=200/-.
Question is-.
12 chair + 3table = ?
12 * 200 + 3 * 500= 2400 + 1500 = 3900/-.
Then, 5 chair= 2 tables.
So, 15 chair + 2 table= 4000/- (given).
Means;
5c = 1000/-.
5c = 1000/-.
5c = 1000/-.
2t = 1000 (since 5c=2tables).
Then, 1 table = 1000/2.
=500/-.
1 chair = 1000/5.
=200/-.
Question is-.
12 chair + 3table = ?
12 * 200 + 3 * 500= 2400 + 1500 = 3900/-.
(1)
Niveditha said:
8 years ago
10chairs=4tables.
Given that ( 15chairs+2tables=4000).
so (6tables+2tables=4000) we got 6 tables here because 4T=10C so 15C=6T
8tables =4000.
1 table =500.
now chairs.
10chairs=4tables hence (4*500=2000).
10chairs=2000.
1chair=200.
now 12chairs+3tables=12*200+3*500=2400+1500=3900.
Given that ( 15chairs+2tables=4000).
so (6tables+2tables=4000) we got 6 tables here because 4T=10C so 15C=6T
8tables =4000.
1 table =500.
now chairs.
10chairs=4tables hence (4*500=2000).
10chairs=2000.
1chair=200.
now 12chairs+3tables=12*200+3*500=2400+1500=3900.
Naveencool said:
9 years ago
Cost of 10C and 4T is same as 15C and 2T.
Total - 4000 either you buy 10c and 4t or 15c or 2t.
Cost will remain the same.
Now 10c = 2000 and 4t = 2000 so 2000/10 and 2000/4 you will get- 200 and 500 so 12c * 200 and 3t * 500.
Now you get 2400 + 1500 = 3900.
Total - 4000 either you buy 10c and 4t or 15c or 2t.
Cost will remain the same.
Now 10c = 2000 and 4t = 2000 so 2000/10 and 2000/4 you will get- 200 and 500 so 12c * 200 and 3t * 500.
Now you get 2400 + 1500 = 3900.
Anna John said:
2 years ago
Chair- x, table-y.
10x= 2y.
when you divide them by 2, you get:
5x = 2y -----------> (1)
15x+2y= 4000
15x+5x= 4000,
20x= 4000.
x= 4000/20= 200.
y=5x/2= 5*200/2= 500.
The total of 12 chairs and 3 tables is:
12 * 200 + 3 * 500 = 3900.
10x= 2y.
when you divide them by 2, you get:
5x = 2y -----------> (1)
15x+2y= 4000
15x+5x= 4000,
20x= 4000.
x= 4000/20= 200.
y=5x/2= 5*200/2= 500.
The total of 12 chairs and 3 tables is:
12 * 200 + 3 * 500 = 3900.
(5)
Ansha said:
3 years ago
15C+2T=4000
12C+3T=?
8/4000 = 500( 15Chairs = 6 tables +2 tables =8 tables) table cost = 500.
4000-1000 = 3000(sub).
3000/15 = 200(chair cost=200),
12x200 = 2400,
3x500 = 1500.
2400 + 1500 = 3900(Answer).
12C+3T=?
8/4000 = 500( 15Chairs = 6 tables +2 tables =8 tables) table cost = 500.
4000-1000 = 3000(sub).
3000/15 = 200(chair cost=200),
12x200 = 2400,
3x500 = 1500.
2400 + 1500 = 3900(Answer).
(3)
Arshad said:
1 decade ago
10 Chairs = 4 tables.
5 Chairs = 2 tables.
15 chairs + 2 tables(5 chairs) = 4000.
20 chairs = 4000.
1 chairs = 200.
1 tables = 2.5 chairs.
2.5*200 = 500.
12C+3T = 12*200+3*500 = 2400+1500 = 3900.
5 Chairs = 2 tables.
15 chairs + 2 tables(5 chairs) = 4000.
20 chairs = 4000.
1 chairs = 200.
1 tables = 2.5 chairs.
2.5*200 = 500.
12C+3T = 12*200+3*500 = 2400+1500 = 3900.
(2)
Martin said:
1 decade ago
10c=4t
15c+2t=4000
take the cost of c & t is 2000 b'coz 10c + 4t cost is same. and divid 2000 by 10 as well as 4 and get c & t cost as,
1t-500
1c-200
therefore,
12c-2400 + 3t-1500 = 3900.
15c+2t=4000
take the cost of c & t is 2000 b'coz 10c + 4t cost is same. and divid 2000 by 10 as well as 4 and get c & t cost as,
1t-500
1c-200
therefore,
12c-2400 + 3t-1500 = 3900.
Nayshi said:
4 months ago
10 chairs X =4 Tables Y.
Then, 10X =4Y.
Divide both sides by 2.
5x = 2y came,
5x multiplication equal to reciprocal divide & Keep it;
X in the left side only take 5,
Like this X = 5/2 Y.
Then, 10X =4Y.
Divide both sides by 2.
5x = 2y came,
5x multiplication equal to reciprocal divide & Keep it;
X in the left side only take 5,
Like this X = 5/2 Y.
(2)
Ashok kothimerla said:
9 years ago
I can't understand, please tell me a simple method.
According to me the solution.
One table =250.
One chair=200.
Then,
12c * 200 = 2400 3t * 250=750.
Total =3150 not 3900.
According to me the solution.
One table =250.
One chair=200.
Then,
12c * 200 = 2400 3t * 250=750.
Total =3150 not 3900.
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