Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 3)
3.
The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
Rs. 3500
Rs. 3750
Rs. 3840
Rs. 3900
Answer: Option
Explanation:

Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.

Then, 10x = 4y   or   y = 5 x.
2

15x + 2y = 4000

15x + 2 x 5 x = 4000
2

20x = 4000

x = 200.

So, y = 5 x 200 = 500.
2

Hence, the cost of 12 chairs and 3 tables = 12x + 3y

    = Rs. (2400 + 1500)

    = Rs. 3900.

Discussion:
32 comments Page 2 of 4.

Mohammed Rasel Rana said:   5 years ago
4table=10chair.

So 2 table=(10*-2)÷4 =5chair
Again,
3table=(10*3)÷4=15/2
(5+15) chair=4000.

So, 1chair=4000÷20=200
So,
15/2+12=39/2
So,(39÷2)*200=3900.
Answer:-39000.
(2)

Premchand said:   1 decade ago
10c=4t then 1t=2.5c
15c+2t=4000 that is chair calculation 20c=4000 one chair is 200 12x200=2400 3t=7.5c that is 1500 total counting is 3900

Nouf said:   6 years ago
10 Chair = 4Table.

=>. 2T = 5Chair,
=>15 C= 6Table,

=] 6T + 2T 4000 >>T =500.
C = 2T/5 = 200.
12 * 200+ 3 * 500 = 3900.
(1)

Manojit said:   1 decade ago
@Lorna
15x+2*5x/2=4000 [2is multiply of 5x/2]
15x+5x=4000
20x=4000
x=4000/20
x=200

Dilip said:   1 decade ago
15C+2T=4000
30C+4T=8000

10C=4T

30C+10C=8000
40C=8000
C=200

15(200)+2T=4000
3000+2T=4000
2T=1000
T=500

12(200)+3(500)=3900

Sandeep said:   1 decade ago
Easy way: If 10C=4T then 5C=2T......(1)
given 15C+2T=4000
using (1) we get C=200 & T=500

Hence we can find remaining...
(1)

Mir mushtaq said:   9 years ago
According to me,
Solution :
One tab = 250.
One chair = 200
Then
12c * 200 = 2400
3t * 250 = 750
Total = 3150 not 3900.

GyaniAd said:   3 years ago
@Yash.

5/2 Came By
10x = 4y
=> 5x = 2y
=> y = 5/2x.
(2)

Lorna said:   1 decade ago
How did they get the 20 that was used 20 divide 4000 ?

Pavan said:   9 years ago
I can't understand, please tell me a simple method.


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