Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 8 of 36.
Ameer said:
6 years ago
Let's say the cost price of 20 articles = 100
the selling price of X articles= 100
Gain=25%.
So the cost price of 1 article = 100/20=5.
The selling price of 1 article = 100/X,
Formula= {100/(100+gain%)} * S.P.
5 = {100/(100+25)} *100/X.
Hence X = 16.
the selling price of X articles= 100
Gain=25%.
So the cost price of 1 article = 100/20=5.
The selling price of 1 article = 100/X,
Formula= {100/(100+gain%)} * S.P.
5 = {100/(100+25)} *100/X.
Hence X = 16.
Sumit said:
1 decade ago
Let, C.P of 20 articles = S.P of x articles = y.
So, C.P of 1 article = y/20.
And, S.P of 1 article = y/x.
((y/x-y/20)/(y/20))*100 = 25 ;
[formula: ((S.P-C.P)/C.P)*100 = gain % ].
(20y-xy)/xy = 25/100
(20/x)-1 = 25/100
20/x = 125/100
x = 16.
So, C.P of 1 article = y/20.
And, S.P of 1 article = y/x.
((y/x-y/20)/(y/20))*100 = 25 ;
[formula: ((S.P-C.P)/C.P)*100 = gain % ].
(20y-xy)/xy = 25/100
(20/x)-1 = 25/100
20/x = 125/100
x = 16.
(1)
Imran said:
7 years ago
As per my calculation, the solution is;
Let the cost of 20 articles is y Rs then the sp of x articles is y Rs.
cp of 1 article =y/20.
sp of 1 article = y/x.
so profit= (y/x)-(y/20).
so [{(y/x)-(y/20)}/y]*100=25,
by sovling the value oy x =3.8095.
Let the cost of 20 articles is y Rs then the sp of x articles is y Rs.
cp of 1 article =y/20.
sp of 1 article = y/x.
so profit= (y/x)-(y/20).
so [{(y/x)-(y/20)}/y]*100=25,
by sovling the value oy x =3.8095.
Khan said:
6 years ago
Simple method:
Equation is C. P of 20 articles = SP * x.
C. P is always supposed Rs 100,
P=S.P-CP.
25=S.P-100,
S.P=25+100,
S.P=125.
Now
CP=100,
SP=125,
P=25.
Put into equation
C. P * 20 = sp * x,
100 * 20 = 125 * X,
100 * 20/125 = X.
16 = X.
Equation is C. P of 20 articles = SP * x.
C. P is always supposed Rs 100,
P=S.P-CP.
25=S.P-100,
S.P=25+100,
S.P=125.
Now
CP=100,
SP=125,
P=25.
Put into equation
C. P * 20 = sp * x,
100 * 20 = 125 * X,
100 * 20/125 = X.
16 = X.
PUNYAVATHI said:
5 years ago
From the above question:
20 articles cost price=selling price of x articles so,
20*c.p = s.p*x ----> (1)
s.p=c.p+profit ----> (2).
Given profit=25%=>1/4 on the cost price.
from equation 2.
20*c.p=(c.p+1/4(c.p))x;
20 c.p=5/4 c.p*x,
x = 16,
20 articles cost price=selling price of x articles so,
20*c.p = s.p*x ----> (1)
s.p=c.p+profit ----> (2).
Given profit=25%=>1/4 on the cost price.
from equation 2.
20*c.p=(c.p+1/4(c.p))x;
20 c.p=5/4 c.p*x,
x = 16,
Imraz said:
1 decade ago
Here said that cp of 20 article = sp of x article
So, 20*cp=x*sp ------(1)
Lets assume cp=100; from the question it is given that profit percentage=25%
so sp becomes 125
so the equaion 1 can be written as
20*100=x*125
x=(20*100)/125
x=16
So, 20*cp=x*sp ------(1)
Lets assume cp=100; from the question it is given that profit percentage=25%
so sp becomes 125
so the equaion 1 can be written as
20*100=x*125
x=(20*100)/125
x=16
Akash Kalyankar said:
8 years ago
Suppose cost of 1 article is 1 rupees.
The cost of 20 articles is 20 rupees.
1) sp of 20 articles will be 25 (with 25 % profit)
2) what will x be for sp = 20; (as cp 0f 20 = sp )
20 -----> 25.
x ------> 20.
x = 20 * 20 / 25.
x = 16.
The cost of 20 articles is 20 rupees.
1) sp of 20 articles will be 25 (with 25 % profit)
2) what will x be for sp = 20; (as cp 0f 20 = sp )
20 -----> 25.
x ------> 20.
x = 20 * 20 / 25.
x = 16.
Devi said:
5 years ago
Given:
Profit =25%=125%
CP of 20=SP of x
CP*20=SP*X
CP/SP=X/20
CP=20;
SP=X;
In percentage method,
CP = 100% always assume.
100%=x ------>1.
125%=20 ------>2.
Cross multiply or divide the eqn 1 & 2.
Then you will get, x=16.
Profit =25%=125%
CP of 20=SP of x
CP*20=SP*X
CP/SP=X/20
CP=20;
SP=X;
In percentage method,
CP = 100% always assume.
100%=x ------>1.
125%=20 ------>2.
Cross multiply or divide the eqn 1 & 2.
Then you will get, x=16.
David samuel said:
8 years ago
Given
CP of 20 articles = s.p of x articles --> 1.
From formula (s.p=100+p%/100 x c.p).
We get s.p =5/4 c.p --> 2.
Put 2 in 1.
CP of 20 articles = 5/4 c.p of x articles.
CP of 1 article =(5/4 *1/20) c.p of x articles.
Hence we get x = 16.
CP of 20 articles = s.p of x articles --> 1.
From formula (s.p=100+p%/100 x c.p).
We get s.p =5/4 c.p --> 2.
Put 2 in 1.
CP of 20 articles = 5/4 c.p of x articles.
CP of 1 article =(5/4 *1/20) c.p of x articles.
Hence we get x = 16.
Nithya said:
4 years ago
Guys, it just focus only the equation.
Here;
20.cp= x.sp ----------> (1)
Let assume cp=100
Here given gain%=25
Now the equation of sp is;
Sp=(100+gain%)*cp/100.
=(100+25)*100/100
=125.
From equation (1)
20 * 100 = x.125
X = 2000/125
=16.
Here;
20.cp= x.sp ----------> (1)
Let assume cp=100
Here given gain%=25
Now the equation of sp is;
Sp=(100+gain%)*cp/100.
=(100+25)*100/100
=125.
From equation (1)
20 * 100 = x.125
X = 2000/125
=16.
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