Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 7 of 36.
Milan aryal said:
8 years ago
Bina Chand bought two kettles for Rs 1,625. She sold one of them at 20% profit and the others at 20% loss. If the selling price of both kettles are same, find the total cost price of each kettles and find her gain or loss percent in total transaction.
Can anyone solve this?
Can anyone solve this?
Karen said:
2 years ago
CP * 20 = SP * x
SP = CP * 20/x.
Given, profit%=25%.
we know, SP = (100+25)%*CP.
also as found, SP=CP*20/x.
Therefore we can say,
(100+25)% * CP = CP *20/x [cp can be cancelled on both sides]
100+25/100 = 20,
125/100 = 20/x.
Cross multiply;
125x = 2000
x = 2000/125,
x = 16.
SP = CP * 20/x.
Given, profit%=25%.
we know, SP = (100+25)%*CP.
also as found, SP=CP*20/x.
Therefore we can say,
(100+25)% * CP = CP *20/x [cp can be cancelled on both sides]
100+25/100 = 20,
125/100 = 20/x.
Cross multiply;
125x = 2000
x = 2000/125,
x = 16.
(28)
Samrat Ghosh said:
8 years ago
Let Cost price of each is a & selling price of each is b.
So, 20 * a = b * X.... i.e 20a = bx -------> (i)
Again, as the profit is 25% so,
a * 125/100 = b...... i.e, 5a = 4b -------> (ii)
Dividing Equation (i) by (ii),
20a/5a = bx/4b.
or, 4 = x/4.
or, x = 16. (ans)
So, 20 * a = b * X.... i.e 20a = bx -------> (i)
Again, as the profit is 25% so,
a * 125/100 = b...... i.e, 5a = 4b -------> (ii)
Dividing Equation (i) by (ii),
20a/5a = bx/4b.
or, 4 = x/4.
or, x = 16. (ans)
Puneet Goel said:
1 decade ago
Let c.p. IS a rs.
Then C.P. of 20 articles =20a = S.P. of x articles
So S.P. of 1 articles=(20.a)/x
So Gain=((20.a)/x)-(a)=a(20-x)/x
Now as Gain%=gain*100/C.P= ((a(20-x)/x)*100)/a=(20-x)*100/x
25=((20-x)/x)*100 => 25x=2000-100x => x=2000/125 = 16
Hence Proved :)
Then C.P. of 20 articles =20a = S.P. of x articles
So S.P. of 1 articles=(20.a)/x
So Gain=((20.a)/x)-(a)=a(20-x)/x
Now as Gain%=gain*100/C.P= ((a(20-x)/x)*100)/a=(20-x)*100/x
25=((20-x)/x)*100 => 25x=2000-100x => x=2000/125 = 16
Hence Proved :)
Prabhu said:
8 years ago
Say c.p of 20 articles =Rs.100.
S.P of 20 articles = Rs.125 (Because Profit is 25%),
S.P of 1 article = 125/20,
Now S.P of X articles =(125/20)*x =125x/20,
now S.P of X articles = C.P of 20 Articles,
125x/20 = 100,
x= (100*20)/125,
Then value of X =16.
That's it.
S.P of 20 articles = Rs.125 (Because Profit is 25%),
S.P of 1 article = 125/20,
Now S.P of X articles =(125/20)*x =125x/20,
now S.P of X articles = C.P of 20 Articles,
125x/20 = 100,
x= (100*20)/125,
Then value of X =16.
That's it.
Muddasir Nawaz said:
7 years ago
Lets C.P. of 20 articles=100 rupees.
then S.P. of 20 articles = 125 (with 25% profit).
S.P. of 1 article =125/20 = 6.25.
The C.P. and S.P. is equal which is 100. So one can sale 16 articles having the price of 6.25 in 100 rupees.
As following
100/6.25=16.
then S.P. of 20 articles = 125 (with 25% profit).
S.P. of 1 article =125/20 = 6.25.
The C.P. and S.P. is equal which is 100. So one can sale 16 articles having the price of 6.25 in 100 rupees.
As following
100/6.25=16.
Chinmaya said:
1 decade ago
Let SP of 1 article = RS 1.
Then SP of X articles = RS X.
ACCORDING TO GIVEN,
CP of 20 articles = SP of X articles.
CP of 20 articles = RS X.
CP of 1 article = RS X/20.
SP = CP ( 1 + R/100 ).
1 = 125/100 * X/20.
X = 16. ans (this is the most simplest way).
Then SP of X articles = RS X.
ACCORDING TO GIVEN,
CP of 20 articles = SP of X articles.
CP of 20 articles = RS X.
CP of 1 article = RS X/20.
SP = CP ( 1 + R/100 ).
1 = 125/100 * X/20.
X = 16. ans (this is the most simplest way).
Sasha said:
1 decade ago
Let CP for 20 articles be y then one article price = y/20.
SP for x articles is also y, then one article SP = x/y.
Now, since profit is 25%:
Profit on 1 article(out of 20)+CP of one article = SP of 1 article(out of x).
(y/20)*(125/100)=(y/x).
Therefore, x=16.
SP for x articles is also y, then one article SP = x/y.
Now, since profit is 25%:
Profit on 1 article(out of 20)+CP of one article = SP of 1 article(out of x).
(y/20)*(125/100)=(y/x).
Therefore, x=16.
Abhi said:
1 decade ago
Hii.... friends i have done this problem in this method.
Dont know whether correct or wrong.please justify me.
c.p*20=s.p*x
Gain=25%
x=?
we know s.p=(100+gain%)/100 *cp
c.p*20=125/100 *cp *x
we will cancel cp on both sides.
by solving we will get x=16.
Dont know whether correct or wrong.please justify me.
c.p*20=s.p*x
Gain=25%
x=?
we know s.p=(100+gain%)/100 *cp
c.p*20=125/100 *cp *x
we will cancel cp on both sides.
by solving we will get x=16.
Eesan said:
9 years ago
Let the cost price of 1 article = P.
So C.P. of 20 article = 20P.
Now, S.P. of x articles = C.P. of 20 article.
So, S.P. of 1 article = 20P / x.
Profit = S.P - C.P. = 20P/x - P.
Now profit% = ((S.P. - C.P.) * 100)/C.P.
= ((20P / x) - P) * 100/ P = 16.
So C.P. of 20 article = 20P.
Now, S.P. of x articles = C.P. of 20 article.
So, S.P. of 1 article = 20P / x.
Profit = S.P - C.P. = 20P/x - P.
Now profit% = ((S.P. - C.P.) * 100)/C.P.
= ((20P / x) - P) * 100/ P = 16.
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