Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
15
16
18
25
Answer: Option
Explanation:

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

20 - x x 100 = 25
x

2000 - 100x = 25x

125x = 2000

x = 16.

Video Explanation: https://youtu.be/sidqvjUoZxY

Discussion:
353 comments Page 8 of 36.

Vivek said:   1 decade ago
Thank for your explanation sanjeet it is so easy to understand after you explain, I like this site very much.

Roopa said:   1 decade ago
Really nice to join your discussion.

I have simple equation;

c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16

Vinu said:   1 decade ago
Hi kailash awesome shortcut.

Vinay said:   1 decade ago
Please Try to Solve the Problems without any Formulas. Understand the Problem and solve it and your own.

UMESH said:   1 decade ago
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

===> LET CP BE Rs 100
CP OF 20 =2000
SP OF 20 =2000*1.25(PROFIT) = 2500
SP OF 01 =2500/20 =125
THERFORE ANSWER = 2000/125 =16

OR
CP *20 =SP *X
PUT SP=1.25CP
NOW, CP*20=1.25CP*X
CANCEL CP FROM BOTH
X = 20/1.25 =16

Nikhil said:   1 decade ago
Awesome explanation chetan!thanx:).

Rashmi Shukla said:   1 decade ago
Clear explanation sangeet thanks :).

Kapil said:   1 decade ago
@Sanjeet

Why we take selling prize = 5 ?

Nj. said:   1 decade ago
Nice Explanation Umesh!!!!! Good Job!

Vikas said:   1 decade ago
Hi Guys,
U can use a very simple method, i.e.,
Suppose,
C.P of 1 item = Rs.100
So C.P of 20 item = Rs.2000
Now profit is 25% so,
s.p of 1 Item = Rs.125 {125% of C.P}
s.p of x Item = 2000 {= C.P of 20 Items}

Therefor number of x item = 2000/125
= 16 Ans.


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