Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 7 of 36.
Vishal said:
1 decade ago
priya...
in general form.
let the cost of 20 article = y rs
so cost of 1 article= y/20rs
and cost of x article = xy/20
so the profit= price-sailing price/sailing rate
25=(y-x*y/20)/(x*y/20)
by solve this u got 16 answer
in general form.
let the cost of 20 article = y rs
so cost of 1 article= y/20rs
and cost of x article = xy/20
so the profit= price-sailing price/sailing rate
25=(y-x*y/20)/(x*y/20)
by solve this u got 16 answer
Yuri said:
1 decade ago
How we assume cp for 1 article is 1?
If we assume else then?
If we assume else then?
Habib said:
1 decade ago
Its very very simple....
Given, CP(20 Articles)=SP(X articles)...............A
Assume, CP of 1 article is Re.1,
CP of X artilcles is rs.X..............B
CP(20 Articles)=rs.20..................C
So A becomes,
rs.20 = SP(X articles).................D
Now, Profit = SP(X articles) - CP(X articles)
= 20 - x (from B&D)
Hence find profit %, (20-x)/x * 100
Given, CP(20 Articles)=SP(X articles)...............A
Assume, CP of 1 article is Re.1,
CP of X artilcles is rs.X..............B
CP(20 Articles)=rs.20..................C
So A becomes,
rs.20 = SP(X articles).................D
Now, Profit = SP(X articles) - CP(X articles)
= 20 - x (from B&D)
Hence find profit %, (20-x)/x * 100
Haritha said:
1 decade ago
c.p of 20 articles= s.p of x articles .........1
s.p=((100+profit%)/100)*c.p
hence from the above values we get
s.p=(5/4)c.p
substitute in 1 we get
X=16
s.p=((100+profit%)/100)*c.p
hence from the above values we get
s.p=(5/4)c.p
substitute in 1 we get
X=16
Prathyusha said:
1 decade ago
Sundar and sanjeet explanation was nice!.
Good work guys!.
Thanku.
Good work guys!.
Thanku.
Kumar said:
1 decade ago
How it was come by using 2000..i cant understand plz explain detaily
Pankaj said:
1 decade ago
How to solve ( (20/x-1) x100) /25?
Kailash said:
1 decade ago
Profit=x-y/y *100
25=20-y/y*100
25/100=20-y/y
1/4=20-y/y
y =4(20-y)
y =80-4y
5y =80
y =80/5
y =16
This is very shortcut method of this types questions.
25=20-y/y*100
25/100=20-y/y
1/4=20-y/y
y =4(20-y)
y =80-4y
5y =80
y =80/5
y =16
This is very shortcut method of this types questions.
Surya said:
1 decade ago
Very nice explanation thanks to snnjeet.
Priyanka said:
1 decade ago
How 20-x sir ?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers