Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 5 of 36.
Chaitanya Galande said:
5 years ago
Let Cost price be C and Selling price be S.
Therefore we're given;
20C = S * X.
Now we're given 25 % profit percentage therefore.
C= S/125%.
Or
C = (S*100)/125.
We get C= 4S/5.
Now putting this value in equation 1.
We get;
20* 4S/5 = S*X,
On solving S gets canceled out and value of X.
We get
X=16.
Therefore we're given;
20C = S * X.
Now we're given 25 % profit percentage therefore.
C= S/125%.
Or
C = (S*100)/125.
We get C= 4S/5.
Now putting this value in equation 1.
We get;
20* 4S/5 = S*X,
On solving S gets canceled out and value of X.
We get
X=16.
S.p.Bharath said:
1 decade ago
1. Assume any value for cost price.
Let it be Rs.20 (you can assume any value).
Then, according to question, He bought 20 articles each costs Rs. 20.
So 20*20=400.
2. He sells each article at 25% profit. So 25% of C.P Rs. 20 is Rs. 5.
So he sells each article at Rs. 25.25*x = 400. So x = 16.
Let it be Rs.20 (you can assume any value).
Then, according to question, He bought 20 articles each costs Rs. 20.
So 20*20=400.
2. He sells each article at 25% profit. So 25% of C.P Rs. 20 is Rs. 5.
So he sells each article at Rs. 25.25*x = 400. So x = 16.
A.VENUGOPAL said:
10 years ago
Let us problem given profit percentage 25%.
Cost price of articles = 1 rupee.
Then 20 article cost = 20*1 = 20 rupees.
Selling price = x (says).
Now profit% = (profit *100)/cp.
Profit = cp-sp.
So (20-x), profit% = 25%.
(25*20)/100 = 20-x.
Then x =15 rupees. Why we don't use this method ?
Cost price of articles = 1 rupee.
Then 20 article cost = 20*1 = 20 rupees.
Selling price = x (says).
Now profit% = (profit *100)/cp.
Profit = cp-sp.
So (20-x), profit% = 25%.
(25*20)/100 = 20-x.
Then x =15 rupees. Why we don't use this method ?
Ayush said:
9 years ago
@Prabhleen.
Let assume cp of 1 item is a, and sp of one item is b. Then according to question first line.
20a = xb.
Also by profit statement.
sp = (100 + gain%) cp.
=> b=125%a.
A replacing value of b in the previous equation.
=> 20a = x(125%a).
=> x = (20 * 100) /125.
=> x = 16.
Let assume cp of 1 item is a, and sp of one item is b. Then according to question first line.
20a = xb.
Also by profit statement.
sp = (100 + gain%) cp.
=> b=125%a.
A replacing value of b in the previous equation.
=> 20a = x(125%a).
=> x = (20 * 100) /125.
=> x = 16.
Rajesh said:
5 years ago
Then after 25% gain selling price of 20 articles is 2500
Then the selling price of 1 article is 2500/20 = 125.
So according to the question:
The Selling price of x article is equal to the cost price of 20 article.
Hence 125x = 2000.
X = 2000/125 = 16,
Hence the value of x is 16.
Then the selling price of 1 article is 2500/20 = 125.
So according to the question:
The Selling price of x article is equal to the cost price of 20 article.
Hence 125x = 2000.
X = 2000/125 = 16,
Hence the value of x is 16.
Manash said:
9 years ago
Let's assume that the CP of each item is Re 1.
Thus, for 20 items, total CP would be Rs 20.
Given that, he makes a profit of 25%,
ie) He is selling every Re 1 item for Rs. 1.25.
Now, since the CP of 20 items (i.e Rs 20) is equal to the SP of x items, therefore,
x * 1.25 = 20.
=> x= 16.
Thus, for 20 items, total CP would be Rs 20.
Given that, he makes a profit of 25%,
ie) He is selling every Re 1 item for Rs. 1.25.
Now, since the CP of 20 items (i.e Rs 20) is equal to the SP of x items, therefore,
x * 1.25 = 20.
=> x= 16.
Vishal thakur said:
2 years ago
Let Cp of 1 article = y
Then Cp of 20 article = 20y = sp of x article(from cp of 20 articles same as sp of x article)
Now cp of x articles = xy.
Gain = sp of x articles - cp of x articles.
Now profit = gain/cp of x article*100
25=20y-xy/xy * 100.
By solving 5xy/4 = 20y
then 5x =80.
X = 16.
Then Cp of 20 article = 20y = sp of x article(from cp of 20 articles same as sp of x article)
Now cp of x articles = xy.
Gain = sp of x articles - cp of x articles.
Now profit = gain/cp of x article*100
25=20y-xy/xy * 100.
By solving 5xy/4 = 20y
then 5x =80.
X = 16.
(10)
Subhanandhini said:
8 years ago
Hi guys,
Here , Given that S.p = 20x.
Profit = 25%.
We need to find the value of x, which is C.P
Hence, C.P=20x÷125*100
125=20x*100
125=2000x
X = 2000÷125
=16.
Here , Given that S.p = 20x.
Profit = 25%.
We need to find the value of x, which is C.P
Hence, C.P=20x÷125*100
125=20x*100
125=2000x
X = 2000÷125
=16.
Vikas said:
1 decade ago
Hi Guys,
U can use a very simple method, i.e.,
Suppose,
C.P of 1 item = Rs.100
So C.P of 20 item = Rs.2000
Now profit is 25% so,
s.p of 1 Item = Rs.125 {125% of C.P}
s.p of x Item = 2000 {= C.P of 20 Items}
Therefor number of x item = 2000/125
= 16 Ans.
U can use a very simple method, i.e.,
Suppose,
C.P of 1 item = Rs.100
So C.P of 20 item = Rs.2000
Now profit is 25% so,
s.p of 1 Item = Rs.125 {125% of C.P}
s.p of x Item = 2000 {= C.P of 20 Items}
Therefor number of x item = 2000/125
= 16 Ans.
Chetan said:
1 decade ago
Hi guys,
20 article C.P = 100rs(say)
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%)
now consider only S.P
125 rs --->20 articles
100 rs --->? articles
100*20/125=16
That is it simple.
20 article C.P = 100rs(say)
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%)
now consider only S.P
125 rs --->20 articles
100 rs --->? articles
100*20/125=16
That is it simple.
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