Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 4 of 36.
Somu said:
4 years ago
Cp of 1 article is Rs. 1 so 20 articles cp is Rs. 20.
Given 25%profit that means on 1 article there is 25% profit so profit is 0.25 on one article then sp of one article is cp + profit = Rs 1.25.
Cp 20 = here we want 20 for how many articles it becomes Rs. 20 @ sp is Rs 1.25 for 4 articles it is 5 so that Rs. 20, 16 articles.
Given 25%profit that means on 1 article there is 25% profit so profit is 0.25 on one article then sp of one article is cp + profit = Rs 1.25.
Cp 20 = here we want 20 for how many articles it becomes Rs. 20 @ sp is Rs 1.25 for 4 articles it is 5 so that Rs. 20, 16 articles.
(1)
RAJA said:
8 years ago
Assume C.p of 20 articles = rs 20 (ie c.p of 1 articles = rs1).
S.p of x articles = c.p of 20 articles,
S.p of x articles = rs 20.
Then c.p of x articles =?.
They told 25% profit.
Profit % =((s.p - c.p)/c.p)*100.
25 = ((20-c.p)/c.p)*100.
C.p of x articles is rs 16.
So, x articles = 16 because c.p of 1 article = rs 1.
S.p of x articles = c.p of 20 articles,
S.p of x articles = rs 20.
Then c.p of x articles =?.
They told 25% profit.
Profit % =((s.p - c.p)/c.p)*100.
25 = ((20-c.p)/c.p)*100.
C.p of x articles is rs 16.
So, x articles = 16 because c.p of 1 article = rs 1.
Kishore said:
8 years ago
Here ,we dont know the value of s.p but in condition given that , s.p of x articles = 20 articles of c.p.
let c.p of 1 article is 1/-
so,c.p of x article become x/-
as per condition,
s.p of x article is 20/-(s.p of x articles which is equal to c.p of 20 article (i.e 20/-)).
p%=(s.p-c.p)/c.p *100.
=(20-x)/x*100 = 16.
let c.p of 1 article is 1/-
so,c.p of x article become x/-
as per condition,
s.p of x article is 20/-(s.p of x articles which is equal to c.p of 20 article (i.e 20/-)).
p%=(s.p-c.p)/c.p *100.
=(20-x)/x*100 = 16.
Ashima said:
1 decade ago
Let CP of 1 article be 100rs.
p = 25 (because P% = P/CP*100).
SP = 100 +25 = Rs 125 ( P=SP-CP).
No of articles : CP (unitary method)
1 article - Rs 100.
20 articles - Rs 2000.
No. of articles: SP (unitary method)
1 article - Rs 125
x articles - Rs 2000 (remember CP of 20 = SP of x articles)
x= 2000/125 = 16 articles.
p = 25 (because P% = P/CP*100).
SP = 100 +25 = Rs 125 ( P=SP-CP).
No of articles : CP (unitary method)
1 article - Rs 100.
20 articles - Rs 2000.
No. of articles: SP (unitary method)
1 article - Rs 125
x articles - Rs 2000 (remember CP of 20 = SP of x articles)
x= 2000/125 = 16 articles.
Suresh said:
8 years ago
Let C.P. of each article be Re. 2 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
40 - x x 100 = 25.
x
4000 - 100x = 25x,
125x = 4000,
x = 32.
x cannot be equal to 16.
If you presume Rs.1/- as cost price , x becomes 16. If you presume Rs.10/- as cost price, x becomes 160.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
40 - x x 100 = 25.
x
4000 - 100x = 25x,
125x = 4000,
x = 32.
x cannot be equal to 16.
If you presume Rs.1/- as cost price , x becomes 16. If you presume Rs.10/- as cost price, x becomes 160.
Sumanth geras said:
10 years ago
Another method if you do not understand or remember any method.
It may help you. Take cost of 20 articles price 100.
20*5 = 100.
Profit is 25% (i.e 25 rupees).
20*y = 125.
y = 6.25.
So each article price is 6. 25.
Given cost of 20 1 articles is equal to S.P of x articles x*6.25 = 100.
x = 100/6.25 = 16.
It may help you. Take cost of 20 articles price 100.
20*5 = 100.
Profit is 25% (i.e 25 rupees).
20*y = 125.
y = 6.25.
So each article price is 6. 25.
Given cost of 20 1 articles is equal to S.P of x articles x*6.25 = 100.
x = 100/6.25 = 16.
Anisul Islam said:
2 years ago
The selling price of X article is Y.
The selling price of 1 article is Y/X,
The cost price for 20 articles is Y,
The cost price of 1 article is Y/20,
According to the question,
Y/X = Y/20,
XY = 20Y,
X = 20.
At 25% profit,
If the selling price is 125 then the cost price is 100,
= 100/125.
= 100*20/125.
= 16.
The selling price of 1 article is Y/X,
The cost price for 20 articles is Y,
The cost price of 1 article is Y/20,
According to the question,
Y/X = Y/20,
XY = 20Y,
X = 20.
At 25% profit,
If the selling price is 125 then the cost price is 100,
= 100/125.
= 100*20/125.
= 16.
(19)
Soumya said:
10 years ago
C.P of 20 = S.P of x.
20 C.P = S.P x.
C.P/S.P = x/20.
i.e. C.P = x and S.P = 20.
Gain = S.P-C.P.
= 20-x.
So gain% = (gain/C.P)*100.
= (20-x)/x*100 = 25 (given).
= (2000-100x)/x = 25.
2000 = 125x-100x = 2000 = 25x.
x = 2000/25 = 16.
We can calculate this type of question through this method check.
20 C.P = S.P x.
C.P/S.P = x/20.
i.e. C.P = x and S.P = 20.
Gain = S.P-C.P.
= 20-x.
So gain% = (gain/C.P)*100.
= (20-x)/x*100 = 25 (given).
= (2000-100x)/x = 25.
2000 = 125x-100x = 2000 = 25x.
x = 2000/25 = 16.
We can calculate this type of question through this method check.
Scott said:
10 years ago
The question is not that it is too hard to understand, it is that the question makes no sense in plain English. If you are trying to get someone to figure out what the cost of an article is that costs 20 Rs or $ or any other denomination with a 25% profit, then perhaps you should actually ask that question.
Dharmendra said:
1 decade ago
Suppose c.p. of 1 article is Rs. 1
so c.p. of x article is Rs. x.........(1)
now s.p. of x articles is 20.........from the question....(2)
now profit is s.p-c.p = 20-x .............(3)
now use the formula gain%=gain*100/c.p
25=(20-x)*100/x ...........(1)+(3)
now solve it.
so c.p. of x article is Rs. x.........(1)
now s.p. of x articles is 20.........from the question....(2)
now profit is s.p-c.p = 20-x .............(3)
now use the formula gain%=gain*100/c.p
25=(20-x)*100/x ...........(1)+(3)
now solve it.
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