Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
361 comments Page 37 of 37.
Ragavi P said:
2 weeks ago
Let CP be 100.
CP of 20 articles = SP of x articles.
CP * 20 = SP * x.
100 * 20 = SP * x.
2000 = SP * X ---> equation 1.
To find SP :
SP = CP( 1 + Profit%/100).
SP = 100(1 + 25/100).
SP = 100 (125/100),
Hence SP =125 ---> equation 2.
Substitute equation 2 into 1.
2000 = 125 * x.
x = 16.
CP of 20 articles = SP of x articles.
CP * 20 = SP * x.
100 * 20 = SP * x.
2000 = SP * X ---> equation 1.
To find SP :
SP = CP( 1 + Profit%/100).
SP = 100(1 + 25/100).
SP = 100 (125/100),
Hence SP =125 ---> equation 2.
Substitute equation 2 into 1.
2000 = 125 * x.
x = 16.
(3)
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