Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
357 comments Page 33 of 36.
Karu said:
6 years ago
Let us assume,
Cost price of 20 articles(cp) = 20 R/s.
Selling price of x articles(sp) = x R/s.
Formula:
(S.P-C.P)/C.P*100=profit;
20-x/x*100 = 25.
Cost price of 20 articles(cp) = 20 R/s.
Selling price of x articles(sp) = x R/s.
Formula:
(S.P-C.P)/C.P*100=profit;
20-x/x*100 = 25.
Mahesh bruclee said:
6 years ago
Hi guys,
20 article C.P = 100rs(say)
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%)
Now consider only S.P.
125 rs --->20 articles.
100 rs --->? articles.
100*20/125=16.
That is simple.
20 article C.P = 100rs(say)
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%)
Now consider only S.P.
125 rs --->20 articles.
100 rs --->? articles.
100*20/125=16.
That is simple.
Aishu said:
6 years ago
Let C.P of 20 articles be 20rs.
Then S.P of x articles =20rs.
P%=25 (given).
C.P= (100/ (100+p%) ) *S.P.
= (100/ (100+25) ) *20.
=16.
Then S.P of x articles =20rs.
P%=25 (given).
C.P= (100/ (100+p%) ) *S.P.
= (100/ (100+25) ) *20.
=16.
Gopi said:
6 years ago
@Chetan and @Sanjeeth your explanations were good.
Mir Adil Hussain said:
6 years ago
Let C.P of 20 articles = X.
Let S.P be X+20.
By profit% formulae,
125=X+20/X mul by 100.
The answer is 16.
Let S.P be X+20.
By profit% formulae,
125=X+20/X mul by 100.
The answer is 16.
Ashu said:
6 years ago
Nice explain @chetan simple & sweat.
Chaitanya Galande said:
6 years ago
Let Cost price be C and Selling price be S.
Therefore we're given;
20C = S * X.
Now we're given 25 % profit percentage therefore.
C= S/125%.
Or
C = (S*100)/125.
We get C= 4S/5.
Now putting this value in equation 1.
We get;
20* 4S/5 = S*X,
On solving S gets canceled out and value of X.
We get
X=16.
Therefore we're given;
20C = S * X.
Now we're given 25 % profit percentage therefore.
C= S/125%.
Or
C = (S*100)/125.
We get C= 4S/5.
Now putting this value in equation 1.
We get;
20* 4S/5 = S*X,
On solving S gets canceled out and value of X.
We get
X=16.
Mounika said:
6 years ago
Nice explanation. Thank you @Chetan.
Parimala said:
6 years ago
20C=XS
S/c = 20/x = 5/4.
(Given-25%=+1/4profit=1+4/4=5/4).
5-parts20=5*4 =20 ,then x-4parts = 4 * 4 = 16.
Therefore the answer is 16.
S/c = 20/x = 5/4.
(Given-25%=+1/4profit=1+4/4=5/4).
5-parts20=5*4 =20 ,then x-4parts = 4 * 4 = 16.
Therefore the answer is 16.
Syed Tufail Nabi said:
6 years ago
Let C.P of 20 articles=Rs. 100= S.P of 20 articles.
Gain %= 25%.
Therefore s.p of 20 articles= Rs. 125.
Hence S.P of 1 article = Rs. 125/20.
Thus S.P of x articles = 100 = (125/20) * x.
Which gives x = 2000/125= 16 Answer.
Gain %= 25%.
Therefore s.p of 20 articles= Rs. 125.
Hence S.P of 1 article = Rs. 125/20.
Thus S.P of x articles = 100 = (125/20) * x.
Which gives x = 2000/125= 16 Answer.
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