Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 32 of 36.
Amit said:
6 years ago
Simply, the solution is;
Take C.P as 100% always.
Now,
100%=x.
Profit is 25% so 100+25.
125%=20,
Solve for x,
Ans is 16.
Take C.P as 100% always.
Now,
100%=x.
Profit is 25% so 100+25.
125%=20,
Solve for x,
Ans is 16.
Rahul Kumar said:
6 years ago
Since profit=25%, SP=125% of CP ---> 1.
CPx20=SPx(X), the subtitute value of CP in 1, we get;
X=16.
CPx20=SPx(X), the subtitute value of CP in 1, we get;
X=16.
Harish said:
6 years ago
20*c.p = x*s.p
Here s.p is 125% of c.p,since there is a profit of 25%.
125% = 5/4,
Therefore,
20*c.p=5/4 (c.p)*x.
c.p get cancelled.
X=16.
Here s.p is 125% of c.p,since there is a profit of 25%.
125% = 5/4,
Therefore,
20*c.p=5/4 (c.p)*x.
c.p get cancelled.
X=16.
Ruturaj said:
6 years ago
Hi.
20 article cp =sp of x article.
( Cp of 1 article =100 , suppose.
Then cp of 20 article =20*100 = which is equivalent to sp of x article.
So,
X article sp = 2000.
X article cp = 100*x.
(25/100) = (2000-100x)/(100x).
X = 16.
20 article cp =sp of x article.
( Cp of 1 article =100 , suppose.
Then cp of 20 article =20*100 = which is equivalent to sp of x article.
So,
X article sp = 2000.
X article cp = 100*x.
(25/100) = (2000-100x)/(100x).
X = 16.
Kanchan das said:
6 years ago
Cost p = selling p = 20.
Let cp=100.
Sp=125.
125 -------------> 100
1 -------------> 100/125
20 -------------> 100/125 * 20.
So, X = 16.
Let cp=100.
Sp=125.
125 -------------> 100
1 -------------> 100/125
20 -------------> 100/125 * 20.
So, X = 16.
Abhisek said:
6 years ago
Given CP*20 = S.P*x.
And S.P = (100 + gain%)/ 100 *C.P.
Solve the above 2 eqn to get the answer.
And S.P = (100 + gain%)/ 100 *C.P.
Solve the above 2 eqn to get the answer.
Karu said:
6 years ago
Let us assume,
Cost price of 20 articles(cp) = 20 R/s.
Selling price of x articles(sp) = x R/s.
Formula:
(S.P-C.P)/C.P*100=profit;
20-x/x*100 = 25.
Cost price of 20 articles(cp) = 20 R/s.
Selling price of x articles(sp) = x R/s.
Formula:
(S.P-C.P)/C.P*100=profit;
20-x/x*100 = 25.
Mahesh bruclee said:
6 years ago
Hi guys,
20 article C.P = 100rs(say)
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%)
Now consider only S.P.
125 rs --->20 articles.
100 rs --->? articles.
100*20/125=16.
That is simple.
20 article C.P = 100rs(say)
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%)
Now consider only S.P.
125 rs --->20 articles.
100 rs --->? articles.
100*20/125=16.
That is simple.
Aishu said:
5 years ago
Let C.P of 20 articles be 20rs.
Then S.P of x articles =20rs.
P%=25 (given).
C.P= (100/ (100+p%) ) *S.P.
= (100/ (100+25) ) *20.
=16.
Then S.P of x articles =20rs.
P%=25 (given).
C.P= (100/ (100+p%) ) *S.P.
= (100/ (100+25) ) *20.
=16.
Gopi said:
5 years ago
@Chetan and @Sanjeeth your explanations were good.
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