Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
361 comments Page 33 of 37.
Kapil said:
2 decades ago
@Sanjeet
Why we take selling prize = 5 ?
Why we take selling prize = 5 ?
Rashmi Shukla said:
2 decades ago
Clear explanation sangeet thanks :).
Nikhil said:
2 decades ago
Awesome explanation chetan!thanx:).
UMESH said:
2 decades ago
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
===> LET CP BE Rs 100
CP OF 20 =2000
SP OF 20 =2000*1.25(PROFIT) = 2500
SP OF 01 =2500/20 =125
THERFORE ANSWER = 2000/125 =16
OR
CP *20 =SP *X
PUT SP=1.25CP
NOW, CP*20=1.25CP*X
CANCEL CP FROM BOTH
X = 20/1.25 =16
===> LET CP BE Rs 100
CP OF 20 =2000
SP OF 20 =2000*1.25(PROFIT) = 2500
SP OF 01 =2500/20 =125
THERFORE ANSWER = 2000/125 =16
OR
CP *20 =SP *X
PUT SP=1.25CP
NOW, CP*20=1.25CP*X
CANCEL CP FROM BOTH
X = 20/1.25 =16
Vinay said:
2 decades ago
Please Try to Solve the Problems without any Formulas. Understand the Problem and solve it and your own.
Vinu said:
2 decades ago
Hi kailash awesome shortcut.
Roopa said:
2 decades ago
Really nice to join your discussion.
I have simple equation;
c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16
I have simple equation;
c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16
Vivek said:
2 decades ago
Thank for your explanation sanjeet it is so easy to understand after you explain, I like this site very much.
Priyanka said:
2 decades ago
How 20-x sir ?
Surya said:
2 decades ago
Very nice explanation thanks to snnjeet.
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