Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
356 comments Page 33 of 36.
Vinu said:
1 decade ago
Hi kailash awesome shortcut.
Roopa said:
1 decade ago
Really nice to join your discussion.
I have simple equation;
c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16
I have simple equation;
c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16
Vivek said:
1 decade ago
Thank for your explanation sanjeet it is so easy to understand after you explain, I like this site very much.
Priyanka said:
1 decade ago
How 20-x sir ?
Surya said:
1 decade ago
Very nice explanation thanks to snnjeet.
Kailash said:
1 decade ago
Profit=x-y/y *100
25=20-y/y*100
25/100=20-y/y
1/4=20-y/y
y =4(20-y)
y =80-4y
5y =80
y =80/5
y =16
This is very shortcut method of this types questions.
25=20-y/y*100
25/100=20-y/y
1/4=20-y/y
y =4(20-y)
y =80-4y
5y =80
y =80/5
y =16
This is very shortcut method of this types questions.
Pankaj said:
1 decade ago
How to solve ( (20/x-1) x100) /25?
Kumar said:
1 decade ago
How it was come by using 2000..i cant understand plz explain detaily
Prathyusha said:
1 decade ago
Sundar and sanjeet explanation was nice!.
Good work guys!.
Thanku.
Good work guys!.
Thanku.
Haritha said:
1 decade ago
c.p of 20 articles= s.p of x articles .........1
s.p=((100+profit%)/100)*c.p
hence from the above values we get
s.p=(5/4)c.p
substitute in 1 we get
X=16
s.p=((100+profit%)/100)*c.p
hence from the above values we get
s.p=(5/4)c.p
substitute in 1 we get
X=16
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