Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
![]() |
![]() |
20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 31 of 36.
Raghib said:
4 years ago
Let's do it simple way.
Let's assume CP=x and SP=y
First-line says;
20CP=NSP
Let's substitute CP and SP values and we get,
20x=Ny ----- (i) This is our first equation
The second part of the question says;
Profit%=25%.
and we know that Profit%=[(SP-CP) X 100]/CP.
by substituting values we get,
25=[(y-x) X 100]/x.
upon solving we get,
x=(4/5)y ---(ii) this is our equation 2.
by substituting equation (ii) in equation (i) we get,
Ny=20 X (4/5)y.
N=16 -- Hence 16 is our answer.
Let's assume CP=x and SP=y
First-line says;
20CP=NSP
Let's substitute CP and SP values and we get,
20x=Ny ----- (i) This is our first equation
The second part of the question says;
Profit%=25%.
and we know that Profit%=[(SP-CP) X 100]/CP.
by substituting values we get,
25=[(y-x) X 100]/x.
upon solving we get,
x=(4/5)y ---(ii) this is our equation 2.
by substituting equation (ii) in equation (i) we get,
Ny=20 X (4/5)y.
N=16 -- Hence 16 is our answer.
Rony said:
4 years ago
Cp sp profit=25%(fraction value=1/4)
x :20 means cp=4unit & profit = 1unit.
Then sp=5 unit.
Now 5 unit=20 then 4 unit = 16,
Therefore X = 16.
x :20 means cp=4unit & profit = 1unit.
Then sp=5 unit.
Now 5 unit=20 then 4 unit = 16,
Therefore X = 16.
Vishal Thakur said:
4 years ago
S.P of x Articles = C.P of 20 Articles.
[As C.P of each article is taken as Re. 1].
Therefore, C.P of 20 Articles = Rs. 20.
Therefore, S. P of x Articles = Rs. 20.
[As C.P of each article is taken as Re. 1].
Therefore, C.P of 20 Articles = Rs. 20.
Therefore, S. P of x Articles = Rs. 20.
Sonam shah said:
4 years ago
25% = 1 ÷ 5 =
ie,cp = 4
Sp = 5.
1rs = 1article or 20rs sp so
Sp is nt 5.
Now make sp 20,
Sp=5*4,
So cp also 4*4=16,
Now 1article1rs.
Therefore 16articles =16rs.
So no of articles ie x =16.
ie,cp = 4
Sp = 5.
1rs = 1article or 20rs sp so
Sp is nt 5.
Now make sp 20,
Sp=5*4,
So cp also 4*4=16,
Now 1article1rs.
Therefore 16articles =16rs.
So no of articles ie x =16.
Vikash said:
4 years ago
What if we take cp of 20 articles = rs 100,
then sp of x articles become =rs 100,
and let cp of x articles be =rs x,
Then,
(100 - x/x) * 100 = 25,
which gives x = 80.
then sp of x articles become =rs 100,
and let cp of x articles be =rs x,
Then,
(100 - x/x) * 100 = 25,
which gives x = 80.
Dhanushree Shetty said:
4 years ago
100+25%=125
20. ?.
Cross multiply you will get it as 20*125/100;
= 16.
20. ?.
Cross multiply you will get it as 20*125/100;
= 16.
Ak said:
4 years ago
First of all, understand that
Let suppose the c.p of 1 article is 1vs
Then the cost of x article is x rd.
And s.p of x article is equal to 20*1
Which is 20,
And it's given 25%profit which means
25=20-x/x *100,
Then x=16.
Let suppose the c.p of 1 article is 1vs
Then the cost of x article is x rd.
And s.p of x article is equal to 20*1
Which is 20,
And it's given 25%profit which means
25=20-x/x *100,
Then x=16.
Somu said:
4 years ago
Cp of 1 article is Rs. 1 so 20 articles cp is Rs. 20.
Given 25%profit that means on 1 article there is 25% profit so profit is 0.25 on one article then sp of one article is cp + profit = Rs 1.25.
Cp 20 = here we want 20 for how many articles it becomes Rs. 20 @ sp is Rs 1.25 for 4 articles it is 5 so that Rs. 20, 16 articles.
Given 25%profit that means on 1 article there is 25% profit so profit is 0.25 on one article then sp of one article is cp + profit = Rs 1.25.
Cp 20 = here we want 20 for how many articles it becomes Rs. 20 @ sp is Rs 1.25 for 4 articles it is 5 so that Rs. 20, 16 articles.
(1)
Hanisha said:
4 years ago
Awesome and easy solution @Imraz.
Elvina said:
4 years ago
20cp= xsp ---> (1)
Therefore sp= 20cp/x.
profit%= (profit/cp)100= (sp-cp)100
25=( sp-cp)100
Now substitute the value of sp or cp from (1).
25 = (20cp/x - cp)/cp multiplied by 100,
cp will get cancelled and then solve for x to get 16.
Therefore sp= 20cp/x.
profit%= (profit/cp)100= (sp-cp)100
25=( sp-cp)100
Now substitute the value of sp or cp from (1).
25 = (20cp/x - cp)/cp multiplied by 100,
cp will get cancelled and then solve for x to get 16.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers