Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 25 of 36.
Anonymous said:
7 years ago
Hi guys, let me try it in a simpler way.
Let C.P of an article be 'y'.
Hence C.P of 20 articles ==> 20y.
But given that 20y = S.P of x articles.
and C.P of x articles is y*x.
Now the profit percentage is:
((S.P of x articles - C.P of x articles)) / C.P of x articles) * 100.
(20y - xy)/(xy) * 100 = 25 (as given profit is 25%)
y cancels out, so we simplify to get x = 16.
Let C.P of an article be 'y'.
Hence C.P of 20 articles ==> 20y.
But given that 20y = S.P of x articles.
and C.P of x articles is y*x.
Now the profit percentage is:
((S.P of x articles - C.P of x articles)) / C.P of x articles) * 100.
(20y - xy)/(xy) * 100 = 25 (as given profit is 25%)
y cancels out, so we simplify to get x = 16.
Akki said:
7 years ago
Good explanation Thanks @Chetan.
Imran said:
7 years ago
As per my calculation, the solution is;
Let the cost of 20 articles is y Rs then the sp of x articles is y Rs.
cp of 1 article =y/20.
sp of 1 article = y/x.
so profit= (y/x)-(y/20).
so [{(y/x)-(y/20)}/y]*100=25,
by sovling the value oy x =3.8095.
Let the cost of 20 articles is y Rs then the sp of x articles is y Rs.
cp of 1 article =y/20.
sp of 1 article = y/x.
so profit= (y/x)-(y/20).
so [{(y/x)-(y/20)}/y]*100=25,
by sovling the value oy x =3.8095.
Libia said:
7 years ago
Thanks for making an easy solution @Pinaki Chatterjee.
Chandra Mouli said:
7 years ago
Why we have to assume and take Rs 1 here?
Rohit said:
7 years ago
Why we have to assume and take Rs 1 here?
Can you explain in detail? please.
Can you explain in detail? please.
RAVI PRAKASH said:
7 years ago
We have a direct formula. that can help to get the answer.
The selling price = (c.p * 100)/ (profit%) + 100
= (20*100)/ (25 + 100).
= 20*100 /(125) = 20*4/5.
= 4*4.
= 16.
The selling price = (c.p * 100)/ (profit%) + 100
= (20*100)/ (25 + 100).
= 20*100 /(125) = 20*4/5.
= 4*4.
= 16.
Rushikesh said:
7 years ago
We can solve these problem by using another method.
Given 20 C.P.=x S.P --> eq1.
but the profit is 25%.
Therefore, SP=(125/100)*CP.
put above value of SP in eqn 1.
20*CP=x*(125/100)CP.
By solving x=16.
Given 20 C.P.=x S.P --> eq1.
but the profit is 25%.
Therefore, SP=(125/100)*CP.
put above value of SP in eqn 1.
20*CP=x*(125/100)CP.
By solving x=16.
Jyotiranjans Senapati said:
7 years ago
Profit=(20-x).
How it is Possible ?
Profit Means;
For Example One Item Bay 2 Rupees, This Item sell 4 Rupees.
Then Profit 2 Rupees.
Profit How To Calculated.
= Sp-Cp.
How it is Possible ?
Profit Means;
For Example One Item Bay 2 Rupees, This Item sell 4 Rupees.
Then Profit 2 Rupees.
Profit How To Calculated.
= Sp-Cp.
Nayana said:
7 years ago
(20-x/x* 100) explain this step clearly.
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