Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
356 comments Page 16 of 36.
Tarate Shyam Prabhakar said:
1 decade ago
I say,
20 articles are same price of CP and SP then 25% profit is there.
That's why 20+(25% profit).
20 articles are same price of CP and SP then 25% profit is there.
That's why 20+(25% profit).
Azu said:
1 decade ago
Ok, cool see this guys:
As it was given 20(C.P) = x(S.P)--(1).
And {[(S.P)-(C.P)]/C.P} = 0.25--(2).
Solving, x = 16.
As it was given 20(C.P) = x(S.P)--(1).
And {[(S.P)-(C.P)]/C.P} = 0.25--(2).
Solving, x = 16.
Niru said:
1 decade ago
If the profit % = 25 %.
Then S.P= 125... C.P.
Let this be equation 1.
And it is given that 20 article's cost price is equal to x article's selling price, by converting to equation we get,
20*C.P = x*S.P.
By substituting the first equation in S.P we get,
(20*100)/125.
= 16.
Then S.P= 125... C.P.
Let this be equation 1.
And it is given that 20 article's cost price is equal to x article's selling price, by converting to equation we get,
20*C.P = x*S.P.
By substituting the first equation in S.P we get,
(20*100)/125.
= 16.
Reepen dhital said:
1 decade ago
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20-x).
Then,
25% of x = 20-x.
25x/100 = 20-x.
25x = 2000-100x.
125x = 2000.
i.e x = 15.
S.P. of x articles = Rs. 20.
Profit = Rs. (20-x).
Then,
25% of x = 20-x.
25x/100 = 20-x.
25x = 2000-100x.
125x = 2000.
i.e x = 15.
Vibin joy said:
1 decade ago
Let CP = a; SP = b;
Then 20a = bx;
Given profit % = 25;
So, b-a/a = 1/4;
Then 5a = 4b;
Compare this with 20a = bx;
Ans = x = 16;
Then 20a = bx;
Given profit % = 25;
So, b-a/a = 1/4;
Then 5a = 4b;
Compare this with 20a = bx;
Ans = x = 16;
Ravi said:
1 decade ago
Please help me to solve this equation.
(20 - x)/x*100 = 25.
2000 - 100 x = 25 x.
125 x = 2000.
How we get 25x in first step?
(20 - x)/x*100 = 25.
2000 - 100 x = 25 x.
125 x = 2000.
How we get 25x in first step?
SulekhaReddy said:
1 decade ago
C.P = 20.
S.P = X.
Here C.P of 20 articles is same as S.P of X articles.
So, we can assume that, 20 = X.
So, X = 1/20.
S.P = [(100+profit%)/100]C.P.
X = [(100+25)/100]1/20.
= 125/100*1/20.
= 5/4*1/20 = 5/80.
= 1/16.
So X = 16.
S.P = X.
Here C.P of 20 articles is same as S.P of X articles.
So, we can assume that, 20 = X.
So, X = 1/20.
S.P = [(100+profit%)/100]C.P.
X = [(100+25)/100]1/20.
= 125/100*1/20.
= 5/4*1/20 = 5/80.
= 1/16.
So X = 16.
Jaya Darshini said:
1 decade ago
Please explain me how come we assume that the CP of 1 article is Rs. 1. Why can't we assume some other value?
Govin said:
1 decade ago
Profit = SP-CP.
CP of 20 articles = SP of x articles.
Thus, SP = 20, here assume cost price for this as y.
Profit = 25%.
So, 0.25y = SP-y.
= 0.25y = 20-y.
y = 16.
CP of 20 articles = SP of x articles.
Thus, SP = 20, here assume cost price for this as y.
Profit = 25%.
So, 0.25y = SP-y.
= 0.25y = 20-y.
y = 16.
S.p.Bharath said:
1 decade ago
1. Assume any value for cost price.
Let it be Rs.20 (you can assume any value).
Then, according to question, He bought 20 articles each costs Rs. 20.
So 20*20=400.
2. He sells each article at 25% profit. So 25% of C.P Rs. 20 is Rs. 5.
So he sells each article at Rs. 25.25*x = 400. So x = 16.
Let it be Rs.20 (you can assume any value).
Then, according to question, He bought 20 articles each costs Rs. 20.
So 20*20=400.
2. He sells each article at 25% profit. So 25% of C.P Rs. 20 is Rs. 5.
So he sells each article at Rs. 25.25*x = 400. So x = 16.
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