Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 15 of 36.
SUBHRAJYOTI ROY said:
1 decade ago
PROFIT = 25%.
SO, FOR 1 ARTICLES. IF C.P = 100 THEN, S.P = 125.
∴ 20*C.P = X*S.P[C.P OF 20 ARTICLES = S.P OF X ARTICLES].
=> 20*100 = X*125.
=> X = (20*100)/125.
=> 16 ANS.
SO, FOR 1 ARTICLES. IF C.P = 100 THEN, S.P = 125.
∴ 20*C.P = X*S.P[C.P OF 20 ARTICLES = S.P OF X ARTICLES].
=> 20*100 = X*125.
=> X = (20*100)/125.
=> 16 ANS.
Shrinidhi said:
1 decade ago
Superb explanation to all. Thank you.
Ravi said:
1 decade ago
Hello everyone.
In the given problem 20 article C.P = X.
If one article price is one rupee then X = 20.
In the given problem 20 article C.P = X.
If one article price is one rupee then X = 20.
Md. Ahasanul Kabir said:
1 decade ago
x+x*25/100 = 20.
x+x/4 = 20.
5x = 80.
x = 16.
x+x/4 = 20.
5x = 80.
x = 16.
Samjith P V said:
1 decade ago
x*CP*125/100 = CP*20.
Then x = (20*100)/125.
x =16.
Then x = (20*100)/125.
x =16.
Sampath said:
1 decade ago
We have 20*C.P = X*S.P and we have profit of 25% which means (S.P-C.P)/C.P = 25/100 = 1/4.
= 4*S.P = 5*C.P => C.P = 4/5 S.P substitute it in first line 20*4/5 S.P = X*S.P =>16.
S.P = X*C.P => X = 16.
= 4*S.P = 5*C.P => C.P = 4/5 S.P substitute it in first line 20*4/5 S.P = X*S.P =>16.
S.P = X*C.P => X = 16.
SHARANG RAINA said:
1 decade ago
Let cost of one article be Rs 1.
i.e 4 CP = Rs 1.
Now CP of 20 articles is equal to SP of x article.
SP*x = 20*1.
SP = 20/x.
We know,
SP = (1+ P/100)*CP.
20/x = (1+(25/100))*1.
x = RS.16 Answer.
i.e 4 CP = Rs 1.
Now CP of 20 articles is equal to SP of x article.
SP*x = 20*1.
SP = 20/x.
We know,
SP = (1+ P/100)*CP.
20/x = (1+(25/100))*1.
x = RS.16 Answer.
Tarate Shyam Prabhakar said:
1 decade ago
I say,
20 articles are same price of CP and SP then 25% profit is there.
That's why 20+(25% profit).
20 articles are same price of CP and SP then 25% profit is there.
That's why 20+(25% profit).
Azu said:
1 decade ago
Ok, cool see this guys:
As it was given 20(C.P) = x(S.P)--(1).
And {[(S.P)-(C.P)]/C.P} = 0.25--(2).
Solving, x = 16.
As it was given 20(C.P) = x(S.P)--(1).
And {[(S.P)-(C.P)]/C.P} = 0.25--(2).
Solving, x = 16.
Niru said:
1 decade ago
If the profit % = 25 %.
Then S.P= 125... C.P.
Let this be equation 1.
And it is given that 20 article's cost price is equal to x article's selling price, by converting to equation we get,
20*C.P = x*S.P.
By substituting the first equation in S.P we get,
(20*100)/125.
= 16.
Then S.P= 125... C.P.
Let this be equation 1.
And it is given that 20 article's cost price is equal to x article's selling price, by converting to equation we get,
20*C.P = x*S.P.
By substituting the first equation in S.P we get,
(20*100)/125.
= 16.
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