Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
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20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
355 comments Page 13 of 36.
Govin said:
1 decade ago
Profit = SP-CP.
CP of 20 articles = SP of x articles.
Thus, SP = 20, here assume cost price for this as y.
Profit = 25%.
So, 0.25y = SP-y.
= 0.25y = 20-y.
y = 16.
CP of 20 articles = SP of x articles.
Thus, SP = 20, here assume cost price for this as y.
Profit = 25%.
So, 0.25y = SP-y.
= 0.25y = 20-y.
y = 16.
S.p.Bharath said:
1 decade ago
1. Assume any value for cost price.
Let it be Rs.20 (you can assume any value).
Then, according to question, He bought 20 articles each costs Rs. 20.
So 20*20=400.
2. He sells each article at 25% profit. So 25% of C.P Rs. 20 is Rs. 5.
So he sells each article at Rs. 25.25*x = 400. So x = 16.
Let it be Rs.20 (you can assume any value).
Then, according to question, He bought 20 articles each costs Rs. 20.
So 20*20=400.
2. He sells each article at 25% profit. So 25% of C.P Rs. 20 is Rs. 5.
So he sells each article at Rs. 25.25*x = 400. So x = 16.
Gayathri Ganesan said:
1 decade ago
@Jaya Darshini.
By default if no such values provided for computation in sense we assume such small value as possible that so we assume 1 here.
By default if no such values provided for computation in sense we assume such small value as possible that so we assume 1 here.
Gaurav Sharma said:
1 decade ago
C.P. of 20 articles = S.P of x articles = Let Rs 100 (I will write a for article).
Then if C.P. of 20a = Rs 100 (I have taken above).
So C.P. of 1 a = 100/20 = Rs 5.
Now we can take C.P. of x a = Rs 5x.
And S.P of x a = Rs 100 (taken in 1st line).
Now if we have C.P. and SP of X a, so take profit.
i.e (100-5x/5x)100 = 25.
So after solving this you will get x=16.
As I have taken 100 you can take y, 1, or any other variable just we need to equate.
Then if C.P. of 20a = Rs 100 (I have taken above).
So C.P. of 1 a = 100/20 = Rs 5.
Now we can take C.P. of x a = Rs 5x.
And S.P of x a = Rs 100 (taken in 1st line).
Now if we have C.P. and SP of X a, so take profit.
i.e (100-5x/5x)100 = 25.
So after solving this you will get x=16.
As I have taken 100 you can take y, 1, or any other variable just we need to equate.
PRUDHVI said:
1 decade ago
Sp contains cp and profit[25%].
=>x+x/4[25% of x] = 20.
x+x/4 = 20.
=> 5x/4 = 20.
5x = 80.
x = 16.
=>x+x/4[25% of x] = 20.
x+x/4 = 20.
=> 5x/4 = 20.
5x = 80.
x = 16.
Shivanandam said:
1 decade ago
Answer is 15 coming.
If we go with options. A) 15.
Profit% = (25-15)/20*100 = 25% profit.
Then answer is 15 right.
If we go with options. A) 15.
Profit% = (25-15)/20*100 = 25% profit.
Then answer is 15 right.
Sumanth geras said:
1 decade ago
Another method if you do not understand or remember any method.
It may help you. Take cost of 20 articles price 100.
20*5 = 100.
Profit is 25% (i.e 25 rupees).
20*y = 125.
y = 6.25.
So each article price is 6. 25.
Given cost of 20 1 articles is equal to S.P of x articles x*6.25 = 100.
x = 100/6.25 = 16.
It may help you. Take cost of 20 articles price 100.
20*5 = 100.
Profit is 25% (i.e 25 rupees).
20*y = 125.
y = 6.25.
So each article price is 6. 25.
Given cost of 20 1 articles is equal to S.P of x articles x*6.25 = 100.
x = 100/6.25 = 16.
Raviteja said:
1 decade ago
Given that 20 C.P = x S.P.
And S.P/C.P = 1.25.
20/x = 1.25.
x = 20/1.25.
x = 16.
And S.P/C.P = 1.25.
20/x = 1.25.
x = 20/1.25.
x = 16.
Kumar said:
1 decade ago
I can't understand about xy please explain.
Shameer said:
1 decade ago
Use the formula:
CP = (SP*100)/(100+profit).
CP = (20*100)/(100+25).
CP = 16.
CP = (SP*100)/(100+profit).
CP = (20*100)/(100+25).
CP = 16.
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