Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 11 of 36.
Sasha said:
1 decade ago
Let CP for 20 articles be y then one article price = y/20.
SP for x articles is also y, then one article SP = x/y.
Now, since profit is 25%:
Profit on 1 article(out of 20)+CP of one article = SP of 1 article(out of x).
(y/20)*(125/100)=(y/x).
Therefore, x=16.
SP for x articles is also y, then one article SP = x/y.
Now, since profit is 25%:
Profit on 1 article(out of 20)+CP of one article = SP of 1 article(out of x).
(y/20)*(125/100)=(y/x).
Therefore, x=16.
Abhimanyu said:
1 decade ago
20 article C.P = 100rs(say).
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%).
Now consider only S.P.
125 rs --->20 articles.
100 rs --->? articles.
100*20/125 = 16.
That is it simple.
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%).
Now consider only S.P.
125 rs --->20 articles.
100 rs --->? articles.
100*20/125 = 16.
That is it simple.
Ashwin said:
1 decade ago
Let us consider cost price of 20 articles = 20CP.
And selling price of x articles = xSP.
As he said SP of x articles is same as CP of 20 articles we take,
20CP = xSP.
SP = (20CP)/x.
Profit(.25) = SP-CP/CP.
(20CP-xCP)/xCP = .25.
i.e (20-x)/x = .25.
Implies x = 16.
And selling price of x articles = xSP.
As he said SP of x articles is same as CP of 20 articles we take,
20CP = xSP.
SP = (20CP)/x.
Profit(.25) = SP-CP/CP.
(20CP-xCP)/xCP = .25.
i.e (20-x)/x = .25.
Implies x = 16.
Santosh Dalal said:
1 decade ago
Hello friends.
We can use given below method or not ?
125/100*x = 20.
=> x = 20*100/125.
=> x = 16.
We can use given below method or not ?
125/100*x = 20.
=> x = 20*100/125.
=> x = 16.
Micmysty said:
1 decade ago
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
1. Number of unsold articles = 20-x.
2. In proportion to number of sold articles (x) = 20-x/x.
Number of sold articles is equal to 1 article in 4 = 1/4.
20-x/x = 0.25.
0.25x = 20-x.
0.25x+x = 20.
1.25x = 20.
20/1.25 = 16.
1. Number of unsold articles = 20-x.
2. In proportion to number of sold articles (x) = 20-x/x.
Number of sold articles is equal to 1 article in 4 = 1/4.
20-x/x = 0.25.
0.25x = 20-x.
0.25x+x = 20.
1.25x = 20.
20/1.25 = 16.
SUBHRAJYOTI ROY said:
1 decade ago
PROFIT = 25%.
SO, FOR 1 ARTICLES. IF C.P = 100 THEN, S.P = 125.
∴ 20*C.P = X*S.P[C.P OF 20 ARTICLES = S.P OF X ARTICLES].
=> 20*100 = X*125.
=> X = (20*100)/125.
=> 16 ANS.
SO, FOR 1 ARTICLES. IF C.P = 100 THEN, S.P = 125.
∴ 20*C.P = X*S.P[C.P OF 20 ARTICLES = S.P OF X ARTICLES].
=> 20*100 = X*125.
=> X = (20*100)/125.
=> 16 ANS.
Shrinidhi said:
1 decade ago
Superb explanation to all. Thank you.
Ravi said:
1 decade ago
Hello everyone.
In the given problem 20 article C.P = X.
If one article price is one rupee then X = 20.
In the given problem 20 article C.P = X.
If one article price is one rupee then X = 20.
Md. Ahasanul Kabir said:
1 decade ago
x+x*25/100 = 20.
x+x/4 = 20.
5x = 80.
x = 16.
x+x/4 = 20.
5x = 80.
x = 16.
Samjith P V said:
1 decade ago
x*CP*125/100 = CP*20.
Then x = (20*100)/125.
x =16.
Then x = (20*100)/125.
x =16.
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