Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 14)
14.
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
Answer: Option
Explanation:
| C.P. of 1st transistor = Rs. |  |
100 | x 840 |  |
= Rs. 700. |
| 120 |
| C.P. of 2nd transistor = Rs. | |
100 | x 960 | |
= Rs. 1000 |
| 96 |
So, total C.P. = Rs. (700 + 1000) = Rs. 1700.
Total S.P. = Rs. (840 + 960) = Rs. 1800.
 Gain % = |
|
100 | x 100 | % |
= 5 | 15 | % |
| 1700 | 17 |
Discussion:
41 comments Page 4 of 5.
Shinjinee Ghatak said:
8 years ago
What is the gain% formula? Please tell me.
Sidharth singhaniya said:
7 years ago
Can Anyone solve it by Easy Ratio Method ?
Preet said:
1 decade ago
Please give a shortcut of this question.
Cathy said:
8 years ago
How can we say here loss is incurred?
Dinesh said:
9 years ago
Can we solve this using alligation?
Rohit said:
7 years ago
Very good explanations. Thanks all.
(1)
Bhavna said:
1 decade ago
How gain 100 came in last step ?
Deepak said:
3 years ago
Awesome answer, Thanks @Satya.
(1)
Aastha said:
1 decade ago
How did this 120 come ?
Kiran said:
1 decade ago
Gain % i.e, 100+20=120
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