Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 14)
14.
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
5 15 % loss
17
5 15 % gain
17
6 2 % gain
3
None of these
Answer: Option
Explanation:

C.P. of 1st transistor = Rs. 100 x 840 = Rs. 700.
120

C.P. of 2nd transistor = Rs. 100 x 960 = Rs. 1000
96

So, total C.P. = Rs. (700 + 1000) = Rs. 1700.

Total S.P. = Rs. (840 + 960) = Rs. 1800.

Gain % = 100 x 100 % = 5 15 %
1700 17

Discussion:
41 comments Page 1 of 5.

Osman said:   4 months ago
@Sandeep.

Here, 1800 - 1700 = 100.
Please note it.
(1)

Rakheee said:   2 years ago
20 % of 840 is 678.
Then 840-678 = 168 is the c.p.
How 700 is c.p? Please explain to me.
(5)

Sandeep saha said:   3 years ago
First, find the CP.

WE KNOW THE FORMULA.

P = sp - cp.
CP = sp - p,
X = 840 - 0.2x.
X = 700.

CP = sp + loss.
X = 960 + 0.04x,
X = 1000.

CP total is 1700.
Sp total is 1800.

Gain 100/1700*100.
5.88% or
5*15/17%gain in mixed fraction.
(9)

Deepak said:   3 years ago
Awesome answer, Thanks @Satya.
(1)

Yarshongam said:   3 years ago
Yes, the right answer is 5.88.

How it come 5.15/17%?

Please explain me.

Ameer said:   6 years ago
S.P of 1 translator = 840.
S.P of another translator = 960,
we have to find loss or gain?

Formula is;
c.p={100/(100+gain%)} * s.p,
c.p=100/(100+20%) * 840,
So c.p= 700.

which means gain=840-700 = 140,
Now to second translator;
c.p={100/(100-4%)} * 960,
c.p=1000.

Which means loss=1000-960 = 40,
Now we observed that the total cost price is 1000+700 = 1700,
Total gain = 140-40 = 100.
Gain % = 100 x 100/1700= 5.88%.
(9)

Sidharth singhaniya said:   7 years ago
Can Anyone solve it by Easy Ratio Method ?

Sandeep said:   7 years ago
At last in the gain formula, how can we take gain as 100? please can someone explain.
(1)

Rohit said:   7 years ago
Very good explanations. Thanks all.
(1)

Rakesh said:   7 years ago
How CP can be calculated easily? Can anyone give me the shortcut?


Post your comments here:

Your comments will be displayed after verification.