Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 14)
14.
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
Answer: Option
Explanation:
C.P. of 1st transistor = Rs. | ![]() |
100 | x 840 | ![]() |
= Rs. 700. |
120 |
C.P. of 2nd transistor = Rs. | ![]() |
100 | x 960 | ![]() |
= Rs. 1000 |
96 |
So, total C.P. = Rs. (700 + 1000) = Rs. 1700.
Total S.P. = Rs. (840 + 960) = Rs. 1800.
![]() |
![]() |
100 | x 100 | ![]() |
= 5 | 15 | % |
1700 | 17 |
Discussion:
41 comments Page 3 of 5.
Rakesh said:
7 years ago
How CP can be calculated easily? Can anyone give me the shortcut?
Felix said:
9 years ago
@Priya,
Let we assume 100 if the base cost price is not given.
Let we assume 100 if the base cost price is not given.
Madhav Kakkar said:
1 decade ago
Does anybody know another shortcut it's time consuming method?
Haritha said:
1 decade ago
Can any one tell me why we used 100/120 instead of 120/100?
Meena said:
9 years ago
I am confused please solve this in a simple and clear way.
(1)
Faklandu said:
7 years ago
Why not A? Here it is asking both gain or loss right?
Osman said:
4 months ago
@Sandeep.
Here, 1800 - 1700 = 100.
Please note it.
Here, 1800 - 1700 = 100.
Please note it.
(1)
Mounika said:
1 decade ago
Thanks for your explanation pallavi. Its useful.
Satish said:
8 years ago
How can 5.88 can be converted to 5 * 15/17?
Meenu said:
10 years ago
Please explain it in shortest and easy way.
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