Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 1)
1.
Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is:
4 4 %
7
5 5 %
11
10%
12%
Answer: Option
Explanation:

Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.

Selling Price (S.P.) = Rs. 5800.

Gain = (S.P.) - (C.P.) = Rs.(5800 - 5500) = Rs. 300.

Gain % = 300 x 100 % = 5 5 %
5500 11

Discussion:
148 comments Page 1 of 15.

PRAVEEN said:   2 days ago
CP = 4700 + 800 = 5500,
CP - SP = 5500 - 5800 = 300,
P%= (300/5500) * 100 = 5(5/11)%.

Goku said:   6 days ago
CP = 4700 + 800 = 5500.
SP = 5800.
Gain(profit) = SP-CP = 5800 - 5500 = 300.

Gain% = Gain/CP × 100
Gain% = 300/5500 × 100.
= 300/55.
= 60/11.
Divide 60/11 remainder : 5.
= 5 5/11%.
(2)

Sireen said:   4 months ago
Thanks all for explaining.
(13)

Sakshi said:   5 months ago
CP = 4700 + 800 = 5500,
SP = 5800.
CP - SP = P
5800 - 5500 = 300.

P/CP * 100.
300/5500 * 100 = 5,
= 5/11.
(7)

PREETHI said:   6 months ago
Cp = 4700 + 800 = 5500.
Sp = 5800.
Gain %= (300÷5500) × 100,
= 60/55,
= 5 5/11.
(8)

Anwesha Biswas said:   8 months ago
Cost price of the scooter = Rs. 4700.
As Rs. 800 is spent on repairing, the total C.P is Rs.4700+Rs.800(i.e. Rs.5500).
Now, he sold it at Rs. 5800.
Profit = S.P - C.P.(i.e. Rs. 5800 - Rs. 5500)
= Rs. 300.

Since, profit %= Profit/C.P × 100.
= 5800 - 5500/5800 × 100,
= 60/11% > 5 5/11%.
Hence, the required answer is 5 5/11 %.
(9)

Kalyani said:   11 months ago
Cost price = 4700
For repairs = 800
Total cost price = 4700+ 800 = 5500
Selling price = 5800
Profit = selling price - cost price.
= 5800-5500.
=300.

Profit % = (profit/cost price)* 100,
= (300/5500)*100,
= (300/55).
= 60/11,
= 5 5/11 %.
(34)

Sameer ramchiary said:   1 year ago
CP = 4700 + 800 = 5500
Sp = 5800.

Sp - cp = profit.
5800 - 5500 = 300(p)
P% = p/cp×100.
= 300/5500 × 100.
= 60/11.
(22)

Dhiraj kunwar said:   1 year ago
Thanks for explaining the answer.
(13)

Shirisha SR said:   2 years ago
Good explanation, thanks all.
(52)


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