Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 19 of 24.
Mritika said:
9 years ago
Why have you taken the relative speed here? Please explain.
Puja said:
1 decade ago
Why we need to subtract 46-36 and what is relative speed?
Gowtham R said:
1 decade ago
Can any one explain how the step below ?
2x /36 = 25 /9.
2x /36 = 25 /9.
Waqar said:
9 years ago
Can anyone tell me why only dividing by 36 why not by 46?
Ritika said:
7 years ago
Thanks, @Prati.
You explained it in the very simple way.
You explained it in the very simple way.
Swapnil said:
2 decades ago
How you hav taken distance covered = 2x? please explain.
Mahesh Kariya said:
5 years ago
((46-36)X(5/18)) = (50/18) = (100/36).
2X = 100.
X = 50.
2X = 100.
X = 50.
(1)
M.chandrababu said:
1 decade ago
Please explain how to take distance covered=2x meters.
Taj said:
1 decade ago
Please clarify my doubts.
How it is possible ? 50 m.
How it is possible ? 50 m.
Ryan said:
9 years ago
Where did you get 5/18? Explain me. It is confusing.
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