Aptitude - Problems on Trains - Discussion

It's a simple calculation, in the above question mention that is found out the length of each train.

Formula:
Length= speed ×time.
Speed = 46-36 = 10 ×5/18 = 2.7777.
Time = 36 seconds.

Then,
Length = 2.7777 × 36.
Length = 100 m.
Length of each train = 50m.

Let the speed be 46 & 36 kmph are travel in the same direction so (46-36) = 10 Kmph then change in m/s.
So, 10×5/18 = (25/9)M/S
Distance=speed * time.

They asking the length of each train(2 L )
Distance= speed×time
2 L = (25/9) ×36
2 L = 100
L = 50.

Length of two train = (x + x) = 2x m.
time 36 sec.
Speed = (46-36) = 10 * (5/18) = 25/9 m.
We know that if the train parallel lines in the same direction,
So, t = (L1+L2)/(S1-S2) sec,
so,36 = 2x/(25/9),
2x/36 = 25/9,
18x = 900,
x = 50.
Length of the train is 50 m.

The two trains were at race from the same point. One is not behind the other to cross 2x length, so it will be only x length.

Am I right?

To find the length of each train, you can use the relative speed formula:

Relative Speed = Speed of Faster Train - Speed of Slower Train.
Relative Speed = (46 km/hr - 36 km/hr) = 10 km/hr.
Now, you need to convert the relative speed to meters per second (m/s) because the time is given in seconds:
1 km/hr = 5/18 m/s.

So, 10 km/hr = (10 * 5/18) m/s = (50/18) m/s = (25/9) m/s (approximately)
Now, you can use the formula for distance:
Distance = Speed x Time.
Distance = (25/9) m/s x 36 seconds = (25/9) x 36 meters,
Distance = 100 meters (approximately).
Since the faster train passes the slower train in 36 seconds, the length of each train is 100 meters.

speed of the train 1 = 46km/hr,
speed of the train 2 = 36km/hr,
Relative speed = 46 - 36 = 10km/hr.
t = 36sec.

10 * 5/18 = 50/18 m/sec.
S = d/t.
S = L1 + L2.
Here two trains have equal lengths.
So, its 2L1.
S = 2L1/t.
50/18 = 2L1/36.
L1 = 50m.
So, the length of each train is 50 m.

The answer should be 100.

Since the length of the two trains are equal then in 36 seconds the trains cross each other.

Relative speed = 46 - 36 = 10kmph.
In 3600sec distance covered=10000m.
Therefore distance covered in 36 secs=10000/3600 * 36 = 100.
As the train covers each other and the length is of equal.
So the actual length of each train = 100/2 = 50m.

The answer should be 100, then how it will be 50? can anyone explain?

= [10*5/18]*36.
= 100.
= √100 = 50.
= 50 is the answer.