Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 1 of 24.
Pavani said:
1 week ago
The Length of L1 = length of L2.
L1 = L2.
So, length=2L.
Speed of the train t1 = 46km/hr.
Speed of the train t2 = 36km/hr.
The relative speed = t1 - t2 = 46 - 36 = 10km/hr.
convert to meters a = 10x5/18.
Then time = 36sec.
Now using formula:
2L = 10x5/18 x36.
2L = 100,
L = 50m.
L1 = L2.
So, length=2L.
Speed of the train t1 = 46km/hr.
Speed of the train t2 = 36km/hr.
The relative speed = t1 - t2 = 46 - 36 = 10km/hr.
convert to meters a = 10x5/18.
Then time = 36sec.
Now using formula:
2L = 10x5/18 x36.
2L = 100,
L = 50m.
(7)
Yoo said:
2 months ago
The Length of the train be x.
(u-v) = 46 - 36 = 10km/hr = 25/9,
T = (a+b)/(u-v).
T is the time difference of 36 sec.
(u-v)relative speed train moves in the same direction.
By Substitute all values;
36 = (x+x)/(25/9),
36 * 25/9 = 2x,
x = 50.
(u-v) = 46 - 36 = 10km/hr = 25/9,
T = (a+b)/(u-v).
T is the time difference of 36 sec.
(u-v)relative speed train moves in the same direction.
By Substitute all values;
36 = (x+x)/(25/9),
36 * 25/9 = 2x,
x = 50.
(2)
AMGOTH SRIVASU said:
4 months ago
@All
Speeds of {train1:46km/h},{train2:36km/h}
Across each other in time 36s,
Here the two are in parallel directions travelling where the relative speed of parallel is (train1-train2)/2.
so: length = (t1 - t2)/2 * time.
length= (46km-36km)/2 * 36,
= 10km * 18,
= 10 * (5/18)m*18,
Therefore the length = 50m.
Speeds of {train1:46km/h},{train2:36km/h}
Across each other in time 36s,
Here the two are in parallel directions travelling where the relative speed of parallel is (train1-train2)/2.
so: length = (t1 - t2)/2 * time.
length= (46km-36km)/2 * 36,
= 10km * 18,
= 10 * (5/18)m*18,
Therefore the length = 50m.
(3)
Xyz said:
4 months ago
Length of the train = x.
As both train of equal length = 2x,
Relative speed(faster train-slower train) = (46 - 36) = 10km/hr,
To convert km/hr->m/sec,
10*5/18=25/9 in m/sec.
distance travelled = speed * time.
25/9 * 36 = 100m,
As the total distance covered by both the train is 2x,
2x = 100.
And x = 50(length of each train).
As both train of equal length = 2x,
Relative speed(faster train-slower train) = (46 - 36) = 10km/hr,
To convert km/hr->m/sec,
10*5/18=25/9 in m/sec.
distance travelled = speed * time.
25/9 * 36 = 100m,
As the total distance covered by both the train is 2x,
2x = 100.
And x = 50(length of each train).
(5)
Rudraksha Tyagi said:
4 months ago
In most train problems, especially with same-direction motion, "passes" implies overtaking (faster train starts behind) , leading to 2L.
Am I right?
Am I right?
(5)
Aditya said:
4 months ago
@SRIRAM.
We have to add both train lengths assume with your hand both hands cross each other now slow the process when your left hand and right hand meet the length of your left-hand and right-hand not subtract.
We have to add both train lengths assume with your hand both hands cross each other now slow the process when your left hand and right hand meet the length of your left-hand and right-hand not subtract.
(2)
SRIRAM said:
5 months ago
If both trains were travelling in the same direction then we need to subtract the values, am I right?
Anyone, please clarify to me
Anyone, please clarify to me
(3)
Mhs said:
12 months ago
The answer should be 100, then how it will be 50? can anyone explain?
(10)
Prity Manna said:
1 year ago
Length of two train = (x + x) = 2x m.
time 36 sec.
Speed = (46-36) = 10 * (5/18) = 25/9 m.
We know that if the train parallel lines in the same direction,
So, t = (L1+L2)/(S1-S2) sec,
so,36 = 2x/(25/9),
2x/36 = 25/9,
18x = 900,
x = 50.
Length of the train is 50 m.
time 36 sec.
Speed = (46-36) = 10 * (5/18) = 25/9 m.
We know that if the train parallel lines in the same direction,
So, t = (L1+L2)/(S1-S2) sec,
so,36 = 2x/(25/9),
2x/36 = 25/9,
18x = 900,
x = 50.
Length of the train is 50 m.
(38)
Thimothy said:
1 year ago
Let the speed be 46 & 36 kmph are travel in the same direction so (46-36) = 10 Kmph then change in m/s.
So, 10×5/18 = (25/9)M/S
Distance=speed * time.
They asking the length of each train(2 L )
Distance= speed×time
2 L = (25/9) ×36
2 L = 100
L = 50.
So, 10×5/18 = (25/9)M/S
Distance=speed * time.
They asking the length of each train(2 L )
Distance= speed×time
2 L = (25/9) ×36
2 L = 100
L = 50.
(43)
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