Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
= | ![]() |
10 x | 5 | ![]() |
18 |
= | ![]() |
25 | ![]() |
9 |
![]() |
2x | = | 25 |
36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 20 of 24.
Selvan said:
1 decade ago
If slower train speed is given means what can I do?
Ashwini said:
1 decade ago
Why did you take 36 again two times please explain?
Chandini said:
2 years ago
Why we take 2x/36=25/9?
Can anyone please explain?
Can anyone please explain?
(9)
Jaydeep said:
1 decade ago
Why combined speed is compared to relative speed?
AMANI said:
9 years ago
Please explain it, easily. I can't able to do it.
Vinayak said:
1 decade ago
Can we calculate this example by (a+b) / (u-v)?
RKS NITJ said:
1 decade ago
This is the simplest example of relative speed.
Pabitra said:
6 years ago
Hello, how do you take 5/18? please explain.
Mathan said:
2 decades ago
How you taken this as 2x? please explain.
Mani said:
1 decade ago
Why we difference the speed of 2 trains ?
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