Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
= | ![]() |
10 x | 5 | ![]() |
18 |
= | ![]() |
25 | ![]() |
9 |
![]() |
2x | = | 25 |
36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 18 of 24.
Sunayana said:
1 decade ago
@appu. I understand your way of explaining. Its clear my doubts. Thanks.
Suganthan.m said:
1 decade ago
Distance=sum of length of two trains.
How it is please anyone explain.
How it is please anyone explain.
Srikanth said:
1 decade ago
@Taj.
You just go through the Train formulas you will get clear idea.
You just go through the Train formulas you will get clear idea.
Bhuvana said:
1 decade ago
How it is possible? train length = x metres then distance =2x metres.
Hemant manglani said:
6 years ago
Same Direction (46-36) = 10,
length= speed * time.
(10*5/18)*36 = 50.
length= speed * time.
(10*5/18)*36 = 50.
Mhs said:
1 year ago
The answer should be 100, then how it will be 50? can anyone explain?
(10)
Durgesh Kumar Gupta said:
7 years ago
Why not consider the length of the faster train? Please explain me.
Umer said:
7 years ago
How is the speed of the train mentioned as the length we needed?
Samreen Sultana said:
2 years ago
= [10*5/18]*36.
= 100.
= √100 = 50.
= 50 is the answer.
= 100.
= √100 = 50.
= 50 is the answer.
(9)
Balaji said:
1 decade ago
Here what is mentioning by 18/5 or 5/18... have some confusion
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