Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
50 m
72 m
80 m
82 m
Answer: Option
Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

   = 10 x 5 m/sec
18

   = 25 m/sec
9

2x = 25
36 9

2x = 100

x = 50.

Discussion:
232 comments Page 18 of 24.

Sunayana said:   1 decade ago
@appu. I understand your way of explaining. Its clear my doubts. Thanks.

Suganthan.m said:   1 decade ago
Distance=sum of length of two trains.

How it is please anyone explain.

Srikanth said:   1 decade ago
@Taj.

You just go through the Train formulas you will get clear idea.

Bhuvana said:   1 decade ago
How it is possible? train length = x metres then distance =2x metres.

Hemant manglani said:   6 years ago
Same Direction (46-36) = 10,
length= speed * time.
(10*5/18)*36 = 50.

Mhs said:   1 year ago
The answer should be 100, then how it will be 50? can anyone explain?
(10)

Durgesh Kumar Gupta said:   7 years ago
Why not consider the length of the faster train? Please explain me.

Umer said:   7 years ago
How is the speed of the train mentioned as the length we needed?

Samreen Sultana said:   2 years ago
= [10*5/18]*36.
= 100.
= √100 = 50.
= 50 is the answer.
(9)

Balaji said:   1 decade ago
Here what is mentioning by 18/5 or 5/18... have some confusion


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