Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
= | ![]() |
10 x | 5 | ![]() |
18 |
= | ![]() |
25 | ![]() |
9 |
![]() |
2x | = | 25 |
36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 17 of 24.
Sumi said:
1 decade ago
Hi jayanth
read the problem carefully its given that the trains of equal length
read the problem carefully its given that the trains of equal length
Hari said:
1 decade ago
By using the formula, if we solve the problem in SI unit we get 49.86 as answer.
Sumit Bhagat said:
7 years ago
If length of each train is supposed as x. Then how could distance cover is 2x?
Akshat said:
2 decades ago
It should be mentioned that the faster train started behind the slower train.
SAIKUMAR said:
9 years ago
With these explanations and doubts clear all my doubts.
Thanks to every one.
Thanks to every one.
Jaganmohanreddy said:
9 years ago
@All.
Refer Rajkumar explanation, he explained very well.
Thanks @Rajkumar.
Refer Rajkumar explanation, he explained very well.
Thanks @Rajkumar.
SAM said:
10 years ago
Why should we take relative speed is (46-36) in this case they are parallel?
Venkatesh said:
1 decade ago
Hi jelli, can you give a important equations used in that kind of problems.
Sarita bhuyan said:
8 years ago
Why the distance are substrated?
I mean 460-360. Please explain in detail.
I mean 460-360. Please explain in detail.
Deepu said:
1 decade ago
Should be mentioned that the faster train started behind the slower train.
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