Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
50 m
72 m
80 m
82 m
Answer: Option
Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

   = 10 x 5 m/sec
18

   = 25 m/sec
9

2x = 25
36 9

2x = 100

x = 50.

Discussion:
232 comments Page 16 of 24.

Santu said:   9 years ago
I don't understand last 3 lines. Can anyone explain last 3 lines, that how much get answer 50?

Ammu said:   1 decade ago
Hai how this 36 came? I didn't get it can you please explain clearly? why 2x? why 36 not 46?

Kousalya said:   10 years ago
My question is why we are including ten in the calculation its not given in the data right?

Prajwal said:   1 decade ago
You have taken 2x/36.

Is it the speed of the slower train or the time taken to overtake?

Anil said:   1 decade ago
Its not mention that trains are started at same point, then how can we solve the problem.

Abhishek said:   3 years ago
Why you have done, 2x/36 = 25/9?
And why not 2x/46 = 25/9?

Please explain me clearly.
(8)

Sid said:   1 decade ago
What is relative speed. Please explain me in somewhat detail manner. Cant understand.

Dhruvi said:   6 years ago
Is the faster train behind the slower one? Is that why we are adding length of both?

Ishwar shrestha said:   8 years ago
46-36 = 10,
10*5/18 = 2.77,
2.77*36s = 100,
So, the length of train is 100/2 = 50m.

Anne87 said:   1 decade ago
Good day! I just want to know why you used 2X/36? why did you used 36? Thank you!


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