Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 13 of 24.
Ghari said:
2 years ago
The two trains were at race from the same point. One is not behind the other to cross 2x length, so it will be only x length.
Am I right?
Am I right?
(20)
Rkb said:
9 years ago
T = (L1 + L2)/(S1 + S2),
T * (S1 - S2) = L1 + L2,
36 * 10 * 5/18 = L1 + L2,
100 = L1 + L2.
Given that L1 = L2.
Then,
2L1 = 100.
L1 = 50.
T * (S1 - S2) = L1 + L2,
36 * 10 * 5/18 = L1 + L2,
100 = L1 + L2.
Given that L1 = L2.
Then,
2L1 = 100.
L1 = 50.
Nagarjuna said:
1 decade ago
Length of train is equal to diffence in speeds multiplied by that's all.
46-36=10km/hr.
36sec*10km/hr.
36*10* (5/18) mts/s.
100mts.
46-36=10km/hr.
36sec*10km/hr.
36*10* (5/18) mts/s.
100mts.
Joy khwaka said:
2 years ago
I know most of us are not understanding how 2x/36 comes,
Here is my explanation;
Here 2x is the distance, then 36 is time in seconds.
Here is my explanation;
Here 2x is the distance, then 36 is time in seconds.
(5)
Gurpreet said:
7 years ago
36sc=a+b/u-v.
36 =x+x/46-36kmh,
36s= 2x/10kmh,
36s=2x/10*5/18msec,
36s=2x/25/9msec,
36s=2x*9/25,
36=18x/25,
36*25/18=x,
2*25=x,
50=x.
36 =x+x/46-36kmh,
36s= 2x/10kmh,
36s=2x/10*5/18msec,
36s=2x/25/9msec,
36s=2x*9/25,
36=18x/25,
36*25/18=x,
2*25=x,
50=x.
Dileep kumar said:
1 decade ago
Relative speed = 45-35 = 10.
= 10* (5/18) = 25/9.
Distance = (25/9) *36.
= 25*4.
= 100 FOR BOTH TRAINS.
SO = 50 FOR EACH TRAIN.
= 10* (5/18) = 25/9.
Distance = (25/9) *36.
= 25*4.
= 100 FOR BOTH TRAINS.
SO = 50 FOR EACH TRAIN.
SRIRAM said:
6 months ago
If both trains were travelling in the same direction then we need to subtract the values, am I right?
Anyone, please clarify to me
Anyone, please clarify to me
(3)
Nandhu said:
9 years ago
Here, two trains are equal length & same direction but speed is different that's why we calculate the relative speed = u - v.
Abhishek said:
1 decade ago
Relative speed 46-36= 10 kmph
10 x 5/ 18 = 25/9
in 36 second total distance covered = 100m
100/2= 50 m length of each train.
10 x 5/ 18 = 25/9
in 36 second total distance covered = 100m
100/2= 50 m length of each train.
Pooja said:
1 decade ago
How will you subtract speeds. Because here speeds mentioned are the speeds of two different trains not the same train speeds.
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