Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 12 of 24.
Bharathi said:
10 years ago
I can't understand can anyone explain clearly?
Why we take 2x inspite 2 trains are equal length but they reach different distance only then how it possible?
Why we take 2x inspite 2 trains are equal length but they reach different distance only then how it possible?
Mukesh said:
1 decade ago
Whether the trains are in same or in opposite directions we are to add the lengths of trains for covering distances you can check it.
The answer is correct.
The answer is correct.
Super_sonic said:
1 decade ago
Hello friends,
Can anyone please explain me how the distance covered it 2X he has not provided any information that first train is behind the other train?
Can anyone please explain me how the distance covered it 2X he has not provided any information that first train is behind the other train?
Prashant Gupta said:
6 years ago
Relative length L.R = L1 + L2 = 2L.
Rel. SPEED ... (46- 36)5/18= 10m/s.
Relative Time... T.R =36.
Therefore,
L.R= R.S * R.T.
2L = 10 *36.
L = 50m.
Rel. SPEED ... (46- 36)5/18= 10m/s.
Relative Time... T.R =36.
Therefore,
L.R= R.S * R.T.
2L = 10 *36.
L = 50m.
Rudraksha Tyagi said:
4 months ago
In most train problems, especially with same-direction motion, "passes" implies overtaking (faster train starts behind) , leading to 2L.
Am I right?
Am I right?
(5)
Nikhita said:
8 years ago
Length of both the trains is x+x = 2xkm/hr.
Relative speed = 46-36 = 10km/hr.
Time = 36 sec.
L= 10 * (5/18) * 36.
= 100,
2l= 100,
L= 100/2,
L= 50.
Relative speed = 46-36 = 10km/hr.
Time = 36 sec.
L= 10 * (5/18) * 36.
= 100,
2l= 100,
L= 100/2,
L= 50.
Sarath said:
9 years ago
(X1 + x2/u - v) = 36sec. Formula x1, x2 = x.
(2x/ 46 - 36) = 36sec.
(2x/10) = 36sec.
(10 * 5/18) = (25/9).
(2x/36sec) = (25/9).
2x = 100m.
X = 50m.
(2x/ 46 - 36) = 36sec.
(2x/10) = 36sec.
(10 * 5/18) = (25/9).
(2x/36sec) = (25/9).
2x = 100m.
X = 50m.
Jelli said:
1 decade ago
It's simple
We know the formula
u=(a+b)/x-y
let us take the lengh of the train is z(both trains len are same)
then
36=(z+z)/(46-36)*5/18
z=50m
We know the formula
u=(a+b)/x-y
let us take the lengh of the train is z(both trains len are same)
then
36=(z+z)/(46-36)*5/18
z=50m
Arup said:
1 decade ago
Why we have to subtract (46-36)kmph?
though it is relative speed and both of them are coming to each other it should get added i.e (46+36)
though it is relative speed and both of them are coming to each other it should get added i.e (46+36)
Sagor Chandro said:
1 decade ago
Why length of two train is needed? Please explain. The first train has to cross the length of single train only. Some body explain please.
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