Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 11 of 24.
Vineetha said:
8 years ago
Same direction of trains.
So, (46-36)km/hr = 10km/hr.
Conversion, 10*5/18 =25/9 m/s.
To find length of two trains,
Length=speed*time.
25/9 * 36 =100.
Since 2 trains, 100/2=50.
So, (46-36)km/hr = 10km/hr.
Conversion, 10*5/18 =25/9 m/s.
To find length of two trains,
Length=speed*time.
25/9 * 36 =100.
Since 2 trains, 100/2=50.
Myuri said:
7 years ago
@Tejaswini.
Our question is to find the length of each train. So first we want to find both the length of the trains (2x), here x is a length of one train. So only take 2x.
Our question is to find the length of each train. So first we want to find both the length of the trains (2x), here x is a length of one train. So only take 2x.
Mahesh ojha said:
6 years ago
I think it the faster train has started from behind then only the answer is 50 meter. But if they started from the same point then the total distance covered be the only x.
Nishanth said:
2 years ago
It is correct 100m is the answer, but the trains are each length, the faster has to cross the slower train and the Faster train itself so, we divide it by 2 (2 trains).
(6)
Sudha said:
1 decade ago
We can slove like this
relative speed =10km/hr
distance=speed*time
=(10*5/18)*36
=100m
distance=sum of length of train
since both r equal length
length of each =50m
relative speed =10km/hr
distance=speed*time
=(10*5/18)*36
=100m
distance=sum of length of train
since both r equal length
length of each =50m
Sourav nandi said:
8 years ago
@Sarita.
As per relative motion law. If two particle moves in the same direction then you have to subtract their speed and if in opposite direction the add it.
As per relative motion law. If two particle moves in the same direction then you have to subtract their speed and if in opposite direction the add it.
Md. Habibur Rahman said:
5 years ago
When we calculated relative speed, Why we calculate 2x?
Relative speed means a train will be static. Then we can calculate x only. Am ai right? Please tell me.
Relative speed means a train will be static. Then we can calculate x only. Am ai right? Please tell me.
(1)
Shantanu singh parihar said:
5 years ago
We have 2x cause,
When the faster train passes to slower,
It is covering;
X+X distance(slower train +higher speed train),
So the total distance covered is 2X.
When the faster train passes to slower,
It is covering;
X+X distance(slower train +higher speed train),
So the total distance covered is 2X.
(1)
FERDAOUS HOSSAIN said:
5 years ago
Let, the length of each train is X m.
Both train length is (X+X) =2X m.
Relative speed (46-36) = 10 km/hr=25/9 m/sec.
As per the question,
2X/36 =25/9.
X=50.
Both train length is (X+X) =2X m.
Relative speed (46-36) = 10 km/hr=25/9 m/sec.
As per the question,
2X/36 =25/9.
X=50.
Swapan said:
1 decade ago
Please let me know where does the faster train start.
If the faster train starts behind the slower train the above solution is right otherwise it will be 100.
If the faster train starts behind the slower train the above solution is right otherwise it will be 100.
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