Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 10 of 24.
Ram said:
1 decade ago
There first train is crossing the next train so when it crosses the fast train train will cross it's length and and second train length. So there relative speed and their combined lengths are taken.
Rutvik said:
6 years ago
Please explain 25/9=2.7m/s.
If we use the formula a+b/u-v and if the length is equal then 2a/2.7 = 36.
Which comes to 2a = 36 * 2.7.
i.e.a=36*2.7/2 which comes to 48.6.
Then how it will be 50?
If we use the formula a+b/u-v and if the length is equal then 2a/2.7 = 36.
Which comes to 2a = 36 * 2.7.
i.e.a=36*2.7/2 which comes to 48.6.
Then how it will be 50?
Sunil said:
1 decade ago
If a train has the length x and the other train of same length cross the train of length than distance travel by it must be x so my query is why we are taking length 2x instead of x. Please tell.
Vaishnapriya said:
1 decade ago
In this problem length of two train will be equal therefore L = 2X.
That is distance covered = 2X.
D = SPEED*TIME.
2X = 10*(5/18)*36.
Solve the above equation you can easily get a answer.
That is distance covered = 2X.
D = SPEED*TIME.
2X = 10*(5/18)*36.
Solve the above equation you can easily get a answer.
Shro said:
1 decade ago
We are supposed to find length of each train .
But both train are moving in same direction.
So let the length of each train be x respectively.
So the distace covered will be x+x=2x metres
But both train are moving in same direction.
So let the length of each train be x respectively.
So the distace covered will be x+x=2x metres
Arun said:
1 decade ago
Combine length of train.
1st train - 46000/3600 = 12. 777777778*36=460.
2nd train - 36000/3600 = 10*36=360.
There 460-360 = 100mts for 2 trains.
So each train is 50mts.
ANS : A.
1st train - 46000/3600 = 12. 777777778*36=460.
2nd train - 36000/3600 = 10*36=360.
There 460-360 = 100mts for 2 trains.
So each train is 50mts.
ANS : A.
Thanga said:
1 decade ago
In the question clearly mentioned two trains are same length.
So 46 - 36 : 10
10 *5/18 : 25/9
25/9*36 :.100
So both are 100 meters.
So each train 50 meters.
So 46 - 36 : 10
10 *5/18 : 25/9
25/9*36 :.100
So both are 100 meters.
So each train 50 meters.
Rgvkalp said:
7 years ago
We should consider also the length of the two trains as the faster train can overcome by its length and the slower train.
Therefore, the distance travelled by fa aster train is 2x.
Therefore, the distance travelled by fa aster train is 2x.
Debojit said:
7 years ago
But they are in the same direction, How you add x+ x and not subtract?
Because it's given the same direction if it's opposite direction then it's not a problem. Please explain me.
Because it's given the same direction if it's opposite direction then it's not a problem. Please explain me.
Mohit tiwari said:
9 years ago
When both trains start from same point and one passes another then we should take distance x m, not 2x metre. This condition is possible when fast train is behind the slow train.
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