Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 14 of 24.
Ritik said:
7 years ago
We should consider the extreme case, where starting point of faster train coincides with the finishing point of slower train.
Ram said:
1 decade ago
I think answer is 100 because if we calculate x as 100m then the.
Another train length will be same because both are equal.
Another train length will be same because both are equal.
Roshan Kunwor said:
3 years ago
Because, when the faster train just crosses the slower, they should cover 2x distance since the length of the train is same.
(4)
Sonali said:
1 decade ago
I can't get,please tell me, Why did we get 46-36? why didn't we get (46+36)
and why did we get 2x/36?
Please explain me.
and why did we get 2x/36?
Please explain me.
Subhransu said:
1 decade ago
2x/36 = 25/9.
Please make it cross multiplication simply,
(2x*9) = 25*36),
=>18x = 900.
=>x = 900/18.
=>x = 50m.
Please make it cross multiplication simply,
(2x*9) = 25*36),
=>18x = 900.
=>x = 900/18.
=>x = 50m.
Anoop said:
1 decade ago
I didn't understand that why we are considering speed of slower train even its mention that faster crosses the slower one.
Sarang said:
7 years ago
Distance = speed * time,
D = 46-36= 10* time,
D = 10 5/18* 36,
D= 10 * 5 * 2 = 100,
The length both train is 100/2 = 50.
D = 46-36= 10* time,
D = 10 5/18* 36,
D= 10 * 5 * 2 = 100,
The length both train is 100/2 = 50.
Suvarna said:
2 decades ago
But...
why this is needed???
"Let the length of each train be x metres.
Then, distance covered = 2x metres"
why this is needed???
"Let the length of each train be x metres.
Then, distance covered = 2x metres"
Prasun jana said:
10 years ago
Fast train 46*(5/18)*36 = 460.
2nd train 36*(5/18)*36 = 360.
Difference = 460-360 = 100.
2 train = 100/2 = 50 (ans).
2nd train 36*(5/18)*36 = 360.
Difference = 460-360 = 100.
2 train = 100/2 = 50 (ans).
Afshu said:
2 decades ago
Why can't we assume.
Length of the 1st train as x metres and Length of the second train as y metres?
Please explain.
Length of the 1st train as x metres and Length of the second train as y metres?
Please explain.
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