Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
36
45
48
49
Answer: Option
Explanation:

Relative speed = (60+ 90) km/hr

   = 150 x 5 m/sec
18

   = 125 m/sec.
3

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = 2000 x 3 sec = 48 sec.
125

Discussion:
107 comments Page 5 of 11.

Sabarish said:   1 decade ago
@Dipti
1km=1000m
1hr=60min=3600sec[one min contains 60sec then 60min having 3600sec]

here we want to convert speed(km/hr) into m/sec
so , [(1000/3600)=(5/18)]

have a nice day!

Rajkumar said:   1 decade ago
You all use this formula and do the sum.

The sum which is in opposite direction.

So, formula for time=(L1+L2)/(S1+S2)sec

Amul said:   1 decade ago
Wow super explanation. Im workouting by doing these derivations. All usefull problems with formulas. Thanks.

Sara said:   1 decade ago
Please explain this

(1.10+0.9)/(60+90)*5/18
=48

Prateek said:   1 decade ago
What is the time taken for faster train to cross the slower train?

Harish Raj said:   1 decade ago
@Prateek


The time taken for faster train to cross the slower train is as equal as the time taken for slower train to cross the faster train.

Vaasudevarao said:   1 decade ago
Formula (a+b)/(x+y) =1.10+.90/60+90
=2km/150km/h
=2000m/150*5/18
=2000*3/125
=48 sec

Aarti said:   1 decade ago
Why are you multiplying 150*5/8?

Harsh said:   1 decade ago
If both of them are in km then why convert in m. ?

Ankit said:   1 decade ago
Hi All,

How can be the time taken by the faster train to cross the slower train is same?

The faster train is about 30 Kmph faster than the slower train..

Since the speeds are relative, I think time factor should also be relative.

Please suggest


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