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Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
Problems on Trains
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
36
45
48
49
Answer: Option
Explanation:

Relative speed = (60+ 90) km/hr

   = 150 x 5 m/sec
18

   = 125 m/sec.
3

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = 2000 x 3 sec = 48 sec.
125

Discussion:
109 comments Page 11 of 11.
Raghu said:   9 years ago
2km, when converted using formula, gives 5/9 m/s which is giving the wrong answer. Someone please explain this to me.
Pankaj said:   8 years ago
Hi, the time taken by faster train to cross slower & time taken by slower train to cross faster will be same, right?

So why are we using relative speed formula for all the time. We can use a+b/u+v for calculating time.
Ram said:   8 years ago
Guys, can anyone explain how 41.6666667 was turn into 125/3?
Srinivas said:   7 years ago
Simply, the solution is;

2 km =2000.
=150 * 5/18 is 41.66.
So 2000/41.66 = 48.
Crack said:   7 years ago
I know why 5/18 is calculate. But in this particular math they didn't mention anything related to meter. Only answer is given in second, so we should only convert hr to seconds right? why we converted the km also? train length and speed both are in km, also in answer there's no km unit, only second. So please explain this part.
Gou said:   7 years ago
How to solve (2000*3÷125) ? please explain in breif.
Rony said:   6 years ago
Why not solve in km?

Speed & distance should be in km, right?
Nanda said:   1 year ago
Please explain the answer.
DHANASURIYA M G said:   1 month ago
The time taken by the slower train to cross the faster train is 48 seconds.
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