Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
36
45
48
49
Answer: Option
Explanation:

Relative speed = (60+ 90) km/hr

   = 150 x 5 m/sec
18

   = 125 m/sec.
3

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = 2000 x 3 sec = 48 sec.
125

Discussion:
109 comments Page 4 of 11.

Pavan said:   2 decades ago
Hi arun great job.

Raj said:   2 decades ago
Use simple formula :
1)if 2 things acts in same direction( may be 2 trains or train&jogger)
time they meet t=(x+y)/(u-v)
where x,y-distance of trains or something
u,v-speed's in mps.
2)if 2 things acts in opposite direction:
time they meet t=(x+y)/(u+v)

Ambika said:   2 decades ago
When & why we find relative speed. Plz explain to me I forget

Arulmozhi said:   2 decades ago
When the two trains moving towards or in opposite direction that time we find relative speed.

Am I correct?.

Anjan said:   2 decades ago
Hi frds. Well I have a doubt. How can a slower train ever cross the faster one?.

Kiran said:   2 decades ago
But can you tell me when we subtract (1.10km-0.9km)it becomes(0.2km)
then how can it becomes 2 km. Please explain.

Hadiyal Jignesh said:   2 decades ago
Kiran There is no subtraction in formula we are adding the 1.10 km + 0.9 km = 2 km
right?

Sathish said:   2 decades ago
How to change 2km = 2000m ?

Sundar said:   2 decades ago
@Sathish

1 km = 1000 m

2 km = 1000 x 2 = 2000m.

Himanshu said:   2 decades ago
If the question be:

The time taken by the faster train to cross the slower train in seconds is. ?

What would be the working and answer?


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