Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option
Explanation:
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
| = |  |
36 x | 5 |  m/sec |
| 18 |
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
 Time taken = |
|
360 | sec |
= 36 sec. |
| 10 |
Discussion:
106 comments Page 9 of 11.
Shubham said:
9 years ago
as (a+b/u-v).
(45-9) * 5/18 = 10m/s.
(120 + 240/10) = 36s.
(45-9) * 5/18 = 10m/s.
(120 + 240/10) = 36s.
Niveditha said:
9 years ago
It's better to use shortcut method.
t = a + b /u - v.
t = a + b /u - v.
Priya said:
9 years ago
What is the unit digit of 991^45? Can anyone tell me?
Raj vora said:
9 years ago
Can you please explain why we have to add 240 + 120?
Sandeep said:
9 years ago
Can anyone explain by using formula a + b / u - v?
Atoria M. Horace said:
1 decade ago
I still can't understand how the 5/18 came about.
Kittu said:
8 years ago
@Ishan.
You explained very clearly! thank you.
You explained very clearly! thank you.
Karthik said:
2 decades ago
Y DID U substract 45-9? i didn't understand
Rohan said:
6 years ago
Why is the total distance taken as 240+120?
Sushanto said:
1 decade ago
Why (36 x 5/18) is used? How you get 5/18?
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