Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option
Explanation:
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
| = |  |
36 x | 5 |  m/sec |
| 18 |
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
 Time taken = |
|
360 | sec |
= 36 sec. |
| 10 |
Discussion:
106 comments Page 10 of 11.
Jime said:
7 years ago
Why do we add the distance with direction?
Harika said:
1 decade ago
When we have to calculate relative speed?
Jom said:
2 years ago
Why we consider the length of the track?
(5)
Gokul said:
7 years ago
Here the equation is (l1+l2)/(v2+v1).
Amresh said:
1 decade ago
Total distance should be= 120+240+x.
Prakash said:
10 years ago
How 5/18 will came? Please clarify.
Naveen said:
9 years ago
@Sailesh, What you said is correct.
Afreen said:
7 years ago
For same direction,
t=l1+l2/s1-s2.
t=l1+l2/s1-s2.
(1)
Chetana prajapati said:
2 years ago
Thankyou for explaining the answer.
(8)
Kradeep khera said:
1 decade ago
kmph=kilo meter per hour or km/hr
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