Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option
Explanation:
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= | ![]() |
36 x | 5 | ![]() |
18 |
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
![]() |
![]() |
360 | ![]() |
= 36 sec. |
10 |
Discussion:
106 comments Page 11 of 11.
Sangay said:
6 years ago
How come 5/8? Please explain.
(1)
Anushka said:
1 decade ago
Ya gayatri I agree with you.
Swetty said:
4 years ago
Why 45-9? Explain Please.
(9)
Sarika said:
2 decades ago
Yes, karthik is right.
Shaina said:
1 decade ago
What is kmph?
Nilesh said:
1 decade ago
t = a+b/u-v.
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