Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option
Explanation:
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
| = |  |
36 x | 5 |  m/sec |
| 18 |
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
 Time taken = |
|
360 | sec |
= 36 sec. |
| 10 |
Discussion:
106 comments Page 8 of 11.
Deepak agrawal said:
1 decade ago
@Harika
we calculate the ralative speed when two object are run simultenously in parallel .
we calculate the ralative speed when two object are run simultenously in parallel .
Monica said:
1 decade ago
Why we add track length means because man is running on track? So man gets the track length.
Shubh said:
9 years ago
What will be the shortcut method if trains are moving in opposite directions?
Raju Pathro said:
1 decade ago
We can add jogger length also but it is neglected when compare with train.
Shoyeb said:
7 years ago
What about the extra distance Jogger has travelled in those 36 seconds?
M.V.Rama Krishna Kumar Reddy said:
1 decade ago
For the same direction we get relative speed by subtracting speeds.
Shubhangi nema said:
7 years ago
A jogger is a point object so why we consider the platform length?
Ramsha said:
1 decade ago
Yes @Vedant, I also get the same answer through the same process.
Neel said:
1 decade ago
Thus now the total distance covered by train is 240+120 only.
Raji said:
1 decade ago
What is the difference between 2nd problem and 10th problem?
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