Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
3.6 sec
18 sec
36 sec
72 sec
Answer: Option
Explanation:

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

   = 36 x 5 m/sec
18

   = 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

Time taken = 360 sec = 36 sec.
10
Discussion:
106 comments Page 7 of 11.

Hari said:   1 decade ago
You asked the question for cross the jogger only, but you calculate for the platform, please give me the explanation.

Chirag said:   4 years ago
Why we have taken the distance covered by train as (120m +240m)? why to add the length of the track? Please explain.

Sumi said:   1 decade ago
hi priyanka u understood wrongly relative speed for the objects in same direction is obtained by subtracting only

Dheeraj said:   1 decade ago
@rprabha... no when two things are going in same direction then realtive speed is not sum of that things..

Bahu said:   3 years ago
Because if two trains run in the same direction the Speed of train will decrease to pass another train.

Sanketh said:   2 years ago
@All.

Ahead means behind that's why we should minus the speed because they are in the same direction.
(2)

Jelli said:   1 decade ago
Hi
i think you can use the formula

u=(a+b)/(u-v) (both in a same dir)
=(120+240)/(45-9)*5/18
=36s

Padma said:   1 decade ago
Question asked about at what time train cross man. Man has no length then why we add track length?

Vivek Manve said:   7 years ago
Jogger is also running. So he will cover some distance, that should be taken in calculation right?

Ramesh karthick said:   2 decades ago
Jogger is not idle. He also running. So we done this step 45-9km/hr.

9km/hr is jogger speed.


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